Applying Pythagoras
If the square top of a table has a diagonal of 6 feet, find the area of the table top (in square feet).
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2 solutions
.how did you get 2 x 2 = 3 6 . please,give clear explanation.
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I have edited my answer.
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thanks.just give me one answer-how can i learn hard latex techniques to post calculus,tough looking problems?
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@Mohammad Khaza – In brilliant, they have solutions writing techniques. When writing a solution, you will see it. Just follow the rules and you would be able to write with latex. I hope that was helpful. Also, if you tag any of the staff, probably they have more advice on that issue.
@Mohammad Khaza – Do you want 'Limits'?
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@Munem Shahriar – sure. if you know ,please...
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@Mohammad Khaza – Try the code,
\large \lim_{x\to\infty}
It can be different when used
Put the code inside of \ [ \ ]
Appears as x → ∞ lim
Put the code inside of \ ( \ )
Appears as lim x → ∞
Tell me if this helps. @Mohammad Khaza
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@Munem Shahriar – oh! THAT IS WORKING. GREAT!soon i will post and solve calculus problems
6
2
=
x
2
+
x
2
3 6 = 2 x 2
x 2 = 1 8
fantastically solved!!
Since the diagonal is 6 . By applying Pythagoreas theorem, we have x 2 + x 2 = 6 2 = 3 6 ⟹ 2 x 2 = 3 6 , where x is the side of the square (table top) ⟹ x 2 = 1 8 . Therefore, the area of the square top is 1 8 .