Area problem - 3

Geometry Level 1

Nine identical circles are symmetrically fitted into a square, as shown.

What is the ratio of the red area to blue?

1:1 5:4 4:3 3:2

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6 solutions

Excellent solution - illustrating my precise thought processes.

Thomas Sutcliffe - 3 years, 5 months ago

How do you know the red area = blue area

Aman thegreat - 3 years, 5 months ago

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In my solution, the red area is not equal to the blue area.

A Former Brilliant Member - 3 years, 5 months ago

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No the individual arcs..

Aman thegreat - 3 years, 5 months ago

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@Aman Thegreat Yes they are equal, you can observe that if you inscribed a circle in a square. It is because of symmetry.

A Former Brilliant Member - 3 years, 5 months ago

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@A Former Brilliant Member Yes, that is an intuition . But can you perhaps prove it more rigorously?

Aman thegreat - 3 years, 5 months ago

Because if you circumscribe a circle in a square, you'll notice if you rotate 90 degrees, it is exactly the same, hence the corners have the exact same shape and area

Nat Wright - 3 years, 5 months ago

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How can you prove it geometrically?

Aman thegreat - 3 years, 5 months ago

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@Aman Thegreat If you circumscribed a circle in a square, the point of contact is the midpoint of every edges of the square

Ong Zi Qian - 3 years, 5 months ago

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@Ong Zi Qian What is the Proof for that..

Aman thegreat - 3 years, 5 months ago

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@Aman Thegreat Obviously the diameter of the circle is equal to the edge of square. (Or we can say that the radius of circle is half of the edge of square.)

Therefore, if the circle is circumscribed in a square, the point of contact is the midpoint of every edges of the square.

Ong Zi Qian - 3 years, 4 months ago
Calvin Osborne
Dec 17, 2017

We know that all the star-shaped pieces are congruent, and the red pieces are blue pieces either split in half or into a quarter. We can combine the right and left red pieces and the top and bottom red pieces, leaving us with 4 star-shapes. The 4 corner red pieces form one last star-shape, leaving us with 5 red star-shapes to 4 blue star-shapes.

I had the same thought processes.

David Richner - 3 years, 5 months ago

Please accept my sincere apologies; My eyes read the choice as 5.4. Ed Gray

Edwin Gray - 3 years, 5 months ago
Karthika G Kumar
Dec 18, 2017

An easy solution to this, Assume radius of the circle is r. Area of the blue region can be found out by considering a square joining the centres of all the circles. Area of the red region can be found out by subtracting all the circles area+area of the blue region from the area of the bigger square. From calculations we find that area of blue is 16-4 pie r^2. and area of red is 20-5 pie r^2 . their ratio is 5:4 .

π is spelled Pi not Pie, HAHA it confused me a little

Lee Ye Chuan - 3 years, 5 months ago
Robert DeLisle
Dec 21, 2017

Very clear explanation

Lee Ye Chuan - 3 years, 5 months ago

If you count the decimal percentage of the circles inside blue and red respectively, ex. 0.5+0.5+0.5+0.5+0.25+0.25+0.25+0.25+1=4 for the blue circles, and the same pattern for the red circles, you get the same ratio to the colored sections, as the area covered by the circles, in this instance at least, is in the same accordance to the area covered by the non circle section. This gives you a ratio of circles red to blue equal to 5:4, this the same for colored sections.

Sarthak Bansal
Dec 23, 2017

Let’s denote the constant radius of these circles r r . From the scale of the diagram, we can tell the following: Sidelength S 1 S_1 of the blue square is equal to r + 2 r + r {r}+{2r}+{r} = = 4 r 4r so A r e a ( B l u e ) Area(Blue) = = ( 4 r ) 2 {(4r)}^{2} = = 16 r 2 16{r}^{2} .

We can also see from the diagram that the sidelength S 2 S_2 of the larger square is equal to 3 × 2 r {3}\times{2r} = = 6 r 6r , meaning the total area A r e a ( B l u e ) + A r e a ( R e d ) {Area(Blue)}+{Area(Red)} = = ( 6 r ) 2 {(6r)}^{2} = = 36 r 2 36{r}^{2} . Now, we can solve 36 r 2 16 r 2 = 20 r 2 36{r}^{2} - 16{r}^{2} = 20{r}^{2} = = A r e a ( R e d ) Area(Red) .

Finally, the fun part! 20 r 2 16 r 2 \frac{20{r}^{2}}{16{r}^{2}} = = 5 4 ! ! ! \frac{5}{4}!!!

Note: The 2 squares (Blue Square & Larger Square) are squares, we can tell using the fact that the circles are given CONGRUENT AND SYMMETRICAL. Always try your best to avoid interpreting a problem with the assumption of an accurate diagram.

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