Given that the above diagram is a square and the area of Y = 2 0 1 6 , find the area of X + Z .
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if you can plz explain how did you get (a+2a+b) as the sum of two parallel sides of trapezium Y
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The line running from the top left corner to the bottom right corner is a diagonal of a square.
Consider the white top left triangle. Its angles are 90, 45 and 45 degrees, so it is isoceles. Hence the length of top side of Y is a.
Similarly, the black bottom right triangle is isoceles as well and has side b. Hence the length of the bottom parallel side of Y is 2 a + 2 b − b = 2 a + b .
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Yes... good observation... thanks for the prompt response.... The way I solved this is: Let the middle white area be M... The middle horizontal slice is same as the diagonally cut slice.. (both are halves).... So X + M + Z = Y + M .... Hence, Y = X + Z
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@Rupesh Gesota – Oh! I never thought about it that way. My first instinct was to bash. Thanks for sharing!
I used logic. The area of y was from a segment half the height of the square
We know it's a square because a + (a+b) + b = 2 (a+b)
As the areas of x and z are on the opposite side of the diagonal, then combined they must also equal the area of y in this instance
Therefore
Y = 2016 = X + Z
Good visual solution!
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2 0 1 6 = 2 a + b ( a + 2 a + b ) = 2 3 a 2 + 4 a b + b 2 = 2 a ( 3 a + 4 b ) + 2 b 2 = X + Z Hence X + Z = 2 0 1 6