A 1.4 meter tall man is walking around the earth along the equator. How much farther, in meters, does his head travel than his feet?
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2 π ( r + Δ r ) − 2 π r = 2 π Δ r = 8 . 8
This is simple and nice
To find the distance travelled extra by this man, you must take the radius of the Earth =6731
Multiply it by 2 to get the diameter =13462
And add the man's height =13462 + 1.4 =13463.4
To get the distance travelled by his head we now use the Pi * Diameter formula to find the circumference or the length of the path of the man's head = Pi * 13463.4 =42296.5
Subtract the distance of the diameter of the Earth * Pi we get 42296.5 - (Pi * (6731 * 2))
=8.79
It would be better to express Earth's radius by the value of R , instead of taking it as 6731 in your calculations.
How would the answer change if the equator isn't a perfect circle?
You should have included the man's height twice in the diameter. And Pi is given as 22/7, so you should not use 3.1415... The calculation itself is also wrong: 42296.5 - (Pi * (6731 * 2)) = 4.4 and not 8.79
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There's no need to add the mans height twice. The diastance traveled by the tip of his head will be (radius of the earth + the mans height )X 2π
U cannot say earth's radius to be 6731. U should hv mentioned it in the question itself about the radius.
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The answer does not require you to know the earth's radius.
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So, the answer is the same whether the man walks around the earth or the moon..?
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@Nigel James – This question is even better than the problem!!! Let's assume the Earth has a radius of 12 and the moon has a radius of 5. Then:
C_e=2×22/7×12=75.43
C_(e+1.4)=2×22/7×13.4=84.23
84.23-75.43=8.8
C_m=2×22/7×5=31.43
C_(m+1.4)=2×22/7×6.4=40.23
40.23-31.43=8.8
It doesn't matter what circular object you are on. Your head will always move 8.8 units farther than your feet (if you're 1.4 units tall). Now the real good question is why? :)
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@Mike Gillespie – Let's suppose we are walking on a line,How much farther, in meters, does his head travel than his feet? 0 meters? If we suposse the lenght of the equator to be x and we extend the equator as a line of lenght x,How much farther, in meters, does his head travel than his feet?...
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@Guillermo Templado – As we are not sure how the universe is "flat" or "curved", it is custom to consider a strait line as a line as an arc with a radius = ∞
His feet travel directly along the equator of diameter D, and his head travels along a concentric circle of diameter D+2*1.4.
(D + 2.8) * π - D * π = 2.8 * 22/7 = 8.8
Let the radius of the earth be = r
Radius from earth to the head of the walking man = r + 1.4
Distance traveled by foot of man = 2πr
Distance traveled by head of man = 2π(1.4+r)
Difference in distance traveled = 2π(1.4+r) -2πr
= 7 2 X 2 2 X 1 . 4
= 8 . 8
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Let r be the radius of the earth and r+1.4 be the radius from the center of earth to the head of the man.
Therefore the required difference in the circumferences is 2 π ( r + 1 . 4 ) − 2 π r = 2 π ( 1 . 4 ) = 8 . 8 m