Roots Due to Number Theory.

Algebra Level 3

x 3 x 2 5 x + 1 = 0 \large x^3 - x^2 - 5x + 1 = 0

If α , β \alpha,\beta and γ \gamma are the roots of the equation above, find the value of α + β + γ \lfloor \alpha \rfloor + \lfloor \beta \rfloor + \lfloor \gamma \rfloor .


The answer is 0.

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1 solution

Akshat Sharda
Jan 31, 2018

Let x 3 x 2 5 x + 1 = f ( x ) x^3-x^2-5x+1=f(x) ,

By observation,

f ( 2 ) < 0 f(-2)<0 and f ( 1 ) > 0 f(-1)>0

f ( 0 ) > 0 f(0)>0 and f ( 1 ) < 0 f(1)<0

f ( 2 ) < 0 f(2)<0 and f ( 3 ) > 0 f(3)>0

So, one root each lie in ( 2 , 1 ) , ( 0 , 1 ) (-2,-1),(0,1) and ( 2 , 3 ) (2,3) .

Therefore, the floor function of the roots will give us 2 , 0 -2,0 and 2 2 . So, 2 + 0 + 2 = 0 -2+0+2=0 .

@Akshat Sharda, but what prompted you to check for -2, -1, 0, 1 and 2 only? Why you thought of these numbers only?

Priyanshu Mishra - 3 years, 4 months ago

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What is "differential theory of function"?

Pi Han Goh - 3 years, 4 months ago

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Nothing. Just to check f’(x) And higher derivatives and checking concavity and convexity.

Priyanshu Mishra - 3 years, 4 months ago

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@Priyanshu Mishra I don't see how that is helpful here. Can you elaborate more on this?

Pi Han Goh - 3 years, 4 months ago

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@Pi Han Goh @Pi Han Goh , I basically want to know why he checked the value of function at that points only? Why not other points? That’s my problem only.

Priyanshu Mishra - 3 years, 4 months ago

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@Priyanshu Mishra Please read up Intermediate value theorem .

Pi Han Goh - 3 years, 4 months ago

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