Awesome guys

Number Theory Level 1

2 , 4 , 6 , 3 , 6 , 9 , 4 , 8 , ? I need the proof if anyone solved it other wise i will consider you as a cheater ssee you next time

The answer is 12.

2 solutions

Sarvesh Dubey
Jan 17, 2015

It's simple...first u have considers the multiples of 2(2,4,6)till third one then u considered about 3(3,6,9)also till third one then u considered multiple of 4 so logically u have to consider this also till 3rd multiple therefore the third multiple is 12.. Hope u will upvote the answer...

as you were the first one to solve the problem i upvoted you

sudoku subbu - 6 years, 4 months ago

Thanx bro...

sarvesh dubey - 6 years, 4 months ago

hey you are level 1 in all i cant believe that brilliant is too easy see my levels how is it reply me immediately if you like ny problems follow me.

sudoku subbu - 6 years, 4 months ago

Vishal S
Jan 17, 2015

The 1st three numbers, 2, 4, 6 are consecutive natural multiple of 2.The next three are consecutive natural multiple of 3.The last three should be the consecutive natural multiple of 4

Therefore the missing must be 12 as it is the 3rd multiple of 4

how you can say that it must be a multiple of 4 ???? it may also be 5 no [because the set of natural numbers {2,3,5,7,11 . . . . . . . . }] post a proof that 4 must only come

sudoku subbu - 6 years, 4 months ago

Since 2, 3, 4 are consecutive numbers.So that the last three numbers must be the multiple of 4.A solution to a problem can be approached in different ways

Vishal S - 6 years, 4 months ago

correct i expected this from you good i have posted a solution for the problem once take a look plz

sudoku subbu - 6 years, 4 months ago

@Sudoku Subbu – For which problem

Vishal S - 6 years, 4 months ago

@Vishal S – i dont know correctly i am solving the problems in you activity take a look at my activity didn't you get it in notifications

sudoku subbu - 6 years, 4 months ago