True or False: lo g ( 1 + 2 + 3 ) = lo g 1 + lo g 2 + lo g 3
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Luckily, its true in this case, since ( 1 , 2 , 3 ) is a solution to the equation x + y + z = x y z :P
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It's the only positive solution. :P
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The only positive integer solution. There are infinitely many positive real solutions.
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@Ivan Koswara – The only positive integer solution with exactly 3 terms .
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@Kobe Cheung – Well, the equation is x + y + z = x y z and not a 1 + a 2 + … + a n = a 1 a 2 … a n , so it clearly has 3 terms.
It is true that 1x2x3= 1 + 2 + 3=6. But, log6 > log1 + log2 + log3, because log1=0. The logarithm of the sum of numbers is not always equal to the sum of the individual logarithms of those same numbers. Thus, what you have done here only works for simple arithmetic, not logarithms.
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Incorrect; lo g 6 = lo g ( 1 ⋅ 2 ⋅ 3 ) = lo g 1 + lo g 2 + lo g 3 . Remember the property of logarithms lo g a b = lo g a + lo g b .
lo g ( 1 + 2 + 3 ) = lo g 6 = lo g ( 1 ∗ 2 ∗ 3 )
= lo g 1 + lo g 2 + lo g 3
When does inner addition equal separated addition in logs? I thought the rule was inner multiplication = separated addition and inner division equals separated subtraction? :o
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Inner addition equals to separated addition of logs in this case because 1 + 2 + 3 = 1 ∗ 2 ∗ 3
Given, Log (1+2+3)= log 6 Log 6 can also be written as log 2 × 3 Log 2 × 3 = log 2 + log 3
We know that for any 'log 1' is always equal to '0'...therefore if we add log 1 it won't make much difference.
So log (1+2+3) = log 1 + log 2 + log 3 ☝ this is not a property of logarithms. But in this question it is equal to 'log 1.......log 3'
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Relevant wiki: Properties of Logarithms - Basic
lo g ( 1 + 2 + 3 ) = lo g 6 , lo g 1 + lo g 2 + lo g 3 = lo g ( 1 × 2 × 3 ) = lo g 6