Bad Cutting

A father has 3 identical cupcakes to distribute to his triplets. But, due to a blackout, his triplets directly helped themselves to the cupcakes, and there might be some of them who didn't get 1.

How many different ways could the triplets help themselves to the cupcakes, so that there wasn't an even distribution?


The answer is 9.

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1 solution

Michael Mendrin
Jul 25, 2016

This problem should have specified that the pieces are indistinguishable. Suppose the "3 equal pieces" have colors red, green, blue. Then there would be 27 different ways of distributing the pieces, and 6 ways to do it right, or 21 ways to do it wrong.

If the pieces are indistinguishable, then either one of the triplets gets all 3, or one of the triplets gets 2, while one of the remaining gets 1. The number of ways of getting it wrong is 3 + 3(2) = 9.

In quantum physics, the distinction between distinguishability and indistinguishability plays a crucial role, as for example, if the pieces of the cake are individual electrons, then there can only be a total of 10 ways to distribute them, not 27. This can lead to unexpected statistical results.

But due to a blackout

Pardon me if I'm wrong, but doesn't this line clear things up?

Pi Han Goh - 4 years, 10 months ago

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Let's suppose the father did distribute the pieces equally. How many ways can he do that? Either it's exactly one way to do that, "one piece to each of the triplets", or there are 6 ways to do that, "each of the triplets get one of the 3 equal pieces which really aren't indistinguishable from each other---they're merely all of the same size." Blackout or no blackout.

Maybe I'm trying to litigate this a bit too much, but, remember, this matter of indistinguishability does have awesome consequences in physics. It's far from a trivial matter. Feynman diagrams in Quantum Field Theory would just totally fall apart if it weren't for this "minor issue".

Michael Mendrin - 4 years, 10 months ago

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Give me a moment to think about this. My brain can't process any quantum mechanics stuff.

Pi Han Goh - 4 years, 10 months ago

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@Pi Han Goh I'll give you something to think about. Suppose we have 2 identical black marbles, and 2 boxes in which to put them in at random. What is the probability that there will be 1 marble in each box? it's 1/2. Now, but if we have 2 Boson particles and "2 places" in which to put them at random, what is the probability now? It's 1/3, not 1/4! If they were Fermi particles, the probability becomes 1! If it weren't for this "minor issue", we wouldn't even be here talking to each other this---we wouldn't even exist.

Now, your cake pieces---they're Bosonic, right?

Michael Mendrin - 4 years, 10 months ago

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@Michael Mendrin Hi Michael, this is tooooo advanced for me, so I've submitted a report (yes! to my own problem) so the staffs can take care of it.

Pi Han Goh - 4 years, 10 months ago

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@Pi Han Goh Yeah, I'd like to see how the staff would resolve this. I'm gonna get some popcorn and watch.

Michael Mendrin - 4 years, 10 months ago

0 pending reports

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