∫ sec 2 θ sin θ + sin θ tan 2 θ d θ = ?
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amazing to know that u know integration
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yes i know integration as well u but u don't know me
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@Sumit Cooooool – Now I know you.
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@Akshat Sharda – what do u know about me can u telllll where does i study
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@Sumit Cooooool – C² is this the place where you study??
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@Akshat Sharda – gave the answer that where isaw u i see u everyday and chatted with u on watsapp on independence day
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@Sumit Cooooool – Who are you?????
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@Akshat Sharda – find yourself .......
Why have you written that “amazing to know that you(I) know integration"?
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bcoz from ur face it doesn't seems that u know integration
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∫ sec 2 θ sin θ + sin θ tan 2 θ d θ
⇓
∫ sec 2 θ ( sin θ ) ( 1 + tan 2 θ ) d θ
Now , we know that 1 + t a n 2 θ = s e c 2 θ
Therefore,
∫ sec 2 θ ( sin θ ) ( s e c 2 θ ) d θ
⇓
∫ sin θ d θ ⇒ − cos θ + c