Basics first!

A uniform electric field of 30 N/C 30\text{ N/C} exists along the x x -axis. Calculate the potential difference V B V A { V }_{ B }-{ V }_{ A } between the point A = ( 4 m , 2 m ) A=( 4m,2m) and B = ( 10 m , 5 m ) B=(10m,5m) .


The answer is -180.

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1 solution

Achal Jain
Jun 20, 2016

Δ V = E x Δ x = 30 × ( 10 4 ) = 180 \Delta V={ -E }_{ x }\Delta x=-30\times (10-4)=-180

sir why have you taken it as -E

Deepansh Jindal - 4 years, 12 months ago

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from where do you get that question...??

Deepansh Jindal - 4 years, 12 months ago

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Looked it up online.

Achal Jain - 4 years, 12 months ago

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@Achal Jain at where and from where do you study such type of formulas

i solved it with an easy method...!!!

Deepansh Jindal - 4 years, 12 months ago

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@Deepansh Jindal Tell that to me too! Plz

Achal Jain - 4 years, 12 months ago

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@Achal Jain i thought that the potential at origin is x so potential at A = x-120 (s it is decreasing at 30V/C) and that at B is X -300. so Vb-Va = X-300-(X-120)

which gives us -180V

In this question y coordinates are not considered as they will all be equipotential as electric field is along x axis ... hope it might be correct...

Deepansh Jindal - 4 years, 12 months ago

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@Deepansh Jindal Claps! Clasps!

Achal Jain - 4 years, 12 months ago

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@Achal Jain is it incorrect????

Deepansh Jindal - 4 years, 12 months ago

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@Deepansh Jindal @achal jain l sir please correct if i am wrong...???

Deepansh Jindal - 4 years, 11 months ago

This is because E = d V d r E=-\frac { dV }{ dr } .

Achal Jain - 4 years, 12 months ago

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