A Square of Resistors
Find the equivalent resistance between the points A and B . All of the Resistors are of 1 0 Ω .
The answer is 5.
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2 solutions
I got 0.2 Ohms, idk why: 0.05 + 0.1 + 0.05 = 0.2 Ohms, im right?, lol, 3deep5me this problem.
Hey brother don't you think there is a Wheatstone bridge forming. So I believe the answer is 10, please correct me if I am wrong
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Well can you explain your steps?
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Dude I got the answer right but we know there is a Wheatstone Bridge only if A/B=C/D. If you have HC Verma 2, check in the chapter Electric Current in conductors, (page 181)
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@Department 8 – the wheatstone bridge is totally different .. the terminals of the resistors for which the supposed resistor with no current is not directly attached but attached between the combination
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@Jaswinder Singh – Thanks for that explanation!+1! ⌣ ¨
@Jaswinder Singh – Oh! Never knew of that thanks.
This is wrong weet stone bridge mid resistor will not work and=10 will be the answer
Why it is not wheat stone bridge. Give me concrete reason
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Ok, wait see the following figure:
In this case, there is a Wheatstone bridge and the current won't flow through R 3 (assuming that this is a balanced bridge). I hope you get it.
Because we are not in the context of a wheatstone bridge. It is a simple case of resistors in parallel. It is drawn to resemble the wheatstone bridge, and likely tricked those who did not observe it carefully.
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Thanks sir, and if you were the person who changed the image, thanks again! ⌣ ¨
Must see to that the figure given satisfies the condition of WHEAT STONE BRIDGE. hence the current wont pass through the mid resistor. and the upper and lower give resistance of 20 ohms each and that too in parallel and this gives the equivalent resistance as 10.
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Sorry, but it does not form a Wheatstone bridge, it just appears so.
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plz can u explain me the reason for that?
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@A Former Brilliant Member – It is just a question to trick us. Those who observe it very very carefully, get wrong answers. It is just a case where resistors are parallel to each other
@A Former Brilliant Member – Ok, wait see the following figure:
In this case, there is a Wheatstone bridge and the current won't flow through R 3 (assuming that this is a balanced bridge). I hope you get it.
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@Sravanth C. – ok thnk u. i got it
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@A Former Brilliant Member – Thanks okay, hope you enjoyed the problem! ⌣ ¨
In this it is WHEATSTONE NETWORK current would not flow through 20 phm resistor
The resistor symbols in this circuit indicate that they are all short circuited; Therefore answer should technically be 0.
This is a very simple circuit. In particular, it is not the Wheatsone bridge (see note below). We can easily observe the the circuit can be collapsed into a 1 0 Ω resistor in parallel with two 2 0 Ω resistors as shown in the figure below:
Thus the equivalent resistance will be: R e q 1 = 2 0 1 + 1 0 1 + 2 0 1 = 2 0 1 + 2 + 1 = 5 1 ∴ R e q = 5 Ω
Note: For those who think that this is the Wheatstone bridge, look at the image carefully. The Wheatstone bridge connects the other 2 set of vertices, like so: