Benzene's Derivative

Chemistry Level 5

Consider the following compound:

It undergoes the following reactions with these reagents (in that order):

  1. t t - B u O K \ce{BuOK}
  2. C H C l X 3 \ce{CHCl3} and C H X 3 O N a \ce{CH3ONa} , heat
  3. H X 3 O X + \ce{H3O+} and heat

If the final compound is x x -chloro y , z y, z dimethyl bromobenzene, what is the value of x × y × z + 16 ? x \times y \times z + 16?


The answer is 40.

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1 solution

The compound rearranges to:

The next set of reactions expand the pentane ring and remove M e O H \ce{MeOH} , to give us:

This compound is 2-chloro 3,4-dimethyl bromobenzene.

Hence the answer is 40 \boxed{40}

Please provide the mechanism of the 1st step.

Archit Agrawal - 4 years, 6 months ago

how did u do the first step please provide a mechanism

Zerocool 141 - 4 years, 6 months ago

Hey @Vitthal Yellambalse . , Can you please provide a mechanism , or roughly tell me the mechanism involved in the 1st step . I got it right but I guess I did 1st step wrong! Thanks :)

Aniket Sanghi - 4 years, 4 months ago

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@Aniswar S K @Spandan Senapati

Can you please give some hint?

Harsh Shrivastava - 4 years ago

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i got 2,3 dimethyl 5 chloro bromo benzene

Aniswar S K - 3 years, 11 months ago

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OK how did you proceed?

Harsh Shrivastava - 3 years, 11 months ago

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@Harsh Shrivastava First i did isomerization with the base.

Then the carbene added across the double bond.

Then the base takes up a proton, the double bond is formed, one of the bond of the cyclopropane ring is broken to form a double bond sending the chlorine out

then i did ring expansion, and protonated the och3, it leaves and an alkene is formed.

Aniswar S K - 3 years, 11 months ago

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