Bigger, but how big? [Circles III]

Geometry Level 2

How big is the red portion's area compared to the blue portion's area (only the closed broken-donut shape)? All angles that look perpendicular can be assumed as perpendicular, all lines that look like an unbroken line is a proper line, and all arcs that look like part of a circle, are part of a circle.

Type the comparison as a decimal, if it is 2 5 \frac{2}{5} , type it as 0.40 0.40

Type recurring decimals with two decimal places. 1 7 \frac{1}{7} can be typed as 0.14

It is the ratio of comparison, not the difference

Report area : The report room


The answer is 0.33.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

3 solutions

Fun questions are not in the difficulty, but in the simplicity

Sometimes(rarely for me), even difficult ones are fun!

Vinayak Srivastava - 1 year ago

Log in to reply

I just posted this as a explanation as I have nothing to explain!

Log in to reply

Explanation Paradox?

Vinayak Srivastava - 1 year ago

Log in to reply

@Vinayak Srivastava you got me there lmao XD

Kumudesh Ghosh - 1 year ago
Mahdi Raza
Jun 1, 2020

\[ \begin{align} {\color{Red}{A_{\text{Quarter circle}}}} &= \dfrac{\pi x^2}{4} \\ \\ {\color{Blue}{A_{\text{Quarter donut}}}} &= \dfrac{\pi (2x)^2}{4} - \dfrac{\pi x^2}{4} \implies \dfrac{3 \pi x^2}{4} \\ \\ \dfrac{{\color{Red}{A_{\text{Quarter circle}}}}}{{\color{Blue}{A_{\text{Quarter donut}}}}} &= \dfrac{\frac{\pi x^2}{4}}{ \frac{3 \pi x^2}{4}} = \dfrac{1}{3} \approx \boxed{0.33}

\end{align}\]

A simple solution for a simple question. Thanks @Mahdi Raza !

Log in to reply

Thank you Hamza!

Mahdi Raza - 1 year ago

Colorful solution! :)

Vinayak Srivastava - 1 year ago

Log in to reply

Thank you Vinayak!

Mahdi Raza - 1 year ago

Area of red = π x 2 4 = \dfrac{\pi x^2}{4}

Area of blue = π ( 2 x ) 2 4 π x 2 4 = π ( 4 x 2 ) 4 π x 2 4 = π ( 3 x 2 ) 4 =\dfrac{\pi (2x)^2}{4}-\dfrac{\pi x^2}{4}=\dfrac{\pi (4x^2)}{4}-\dfrac{\pi x^2}{4}=\dfrac{\pi (3x^2)}{4}

Ratio of red to blue = π ( x 2 ) 4 ÷ π ( 3 x 2 ) 4 = 1 3 0.33 =\dfrac{\pi (x^2)}{4}\div\dfrac{\pi (3x^2)}{4}=\dfrac{1}{3}\approx0.33 (to 2 2 decimal places).

Thanks for trying out my question @Vinayak Srivastava !

Log in to reply

You're welcome! BTW, please add the word "ratio" as people might get confused!

Vinayak Srivastava - 1 year ago

Log in to reply

Added as you said. Thanks for the helpful suggestion!

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...