∫ 1 0 2 1 0 x 1 d x = ?
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Happy Birthday! @Nihar Mahajan
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2/10= 2 Oct
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@Mehul Arora – Lol +10 organic compounds. :P
Happy Birthday @Nihar Mahajan , bro wish you a good life.
Thank you.
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Try this
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∫ 1 0 2 1 0 x 1 d x = ( lo g e x ) 1 0 2 1 0 = 3 . 0 4 4