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If Susan is 10, Arabella is 20, and Jim and Neal are both 5, but Richard is 10, how much is Jennifer by the same system?

4 20 6 5

1 solution

Nishant Kumar
Jan 4, 2015

You have to look at how many times the first letter of the name is repeated. For Susan and Richard,its repeated twice so 2 5 = 10, for Neal and Jim, once so 1 5 = 5,for Arabella, three times so 5 2 2 = 20 , Hence for Jennifer is only repeated once... , So Jennifer is 5.

Arabella should be 15 since the letter 'a' is repeated 3 times $\implies3\times5=15$

Marc Vince Casimiro - 6 years, 5 months ago

You have to look at how many times the first letter of the name is repeated. Susan and Richard, twice so 2x5 = 10, Neal and Jim, once so 1x5 = 5, Arabella, three times so 5x2x2 = 20 , Jennifer is only repeated once...

nishant kumar - 6 years, 5 months ago

What? Please explain why Arabella=5x2x2 and not 5x3? It is actually based on the number of syllables in their names. Thus Jen-ni-fer=5x3=15 If not, then please explain otherwise.

Aditi Dwivedi - 6 years, 5 months ago

@Aditi Dwivedi – ok otherwise we can do the same thing in other way the answer is 20.the logic is simple,observe the no of repeated letters in Susan ,it is 1 that is only 's'.So 1 10=10 years.In Arabella there are 2 repeated letters 'a' and 'l' so 2 10=20.Jim and Neal have no repeated letters and in the name with no repeating letters age is calculated as follows Jim=1+3+1=5 that is consonants are given one unit and vowels a e i o u where i stands at 3.Now Neal 1+2+1+1=5years. Jennifer 2 repeated letters so 20.

nishant kumar - 6 years, 5 months ago

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