BRILLIAthon Day 1 1 , Problem 1 1 of 2 2

Chemistry Level 1

( p + ) + ( e ) = (p^+) + (e^-) = (charge)

1 -1 0 0 1 1 None

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5 solutions

Jeff Giff
Jul 17, 2020

A proton is made up of two up quarks( u + 2 3 u^{+\frac23} ) and a down quark ( d 1 3 d^{-\frac13} ), so p + = 1 p^+=1 since 2 × 2 3 1 3 = 1. 2\times \dfrac{2}{3}-\dfrac{1}{3}=1. Also, an electron is e = 1 e^-=-1 , so p + + e = 0 p^++e^-=0 . This is a hydrogen atom.

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LaTeX: 20 20

Algorithmic structure: 3 3

Intelligible Solution: 10 10

Uniqueness: 10 10

Pictures: 0 0

Animations: 0 0

Total: 43 43

Awarded 'BRILLIAthon Star' title for Problem 1 1 .

Yajat Shamji - 11 months ago

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I don't see how that is 20 Latex @Yajat Shamji

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@A Former Brilliant Member It's based not on the amount of LaTeX, but how it's used.

Yajat Shamji - 11 months ago

Also, there's a mistake - he said that e e^{-} = 1 @Yajat Shamji

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@A Former Brilliant Member Oops! But he can edit it.

Yajat Shamji - 11 months ago

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@Yajat Shamji Now you pointed it by mentioning him, so editing mistakes shouldn't be allowed, don't point mistakes till 2:50 pm

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@A Former Brilliant Member It's my duty to help - in this competition, help from the organiser is allowed, unlike others.

Yajat Shamji - 11 months ago

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@Yajat Shamji Oh boy! ok, your contest, your rules

@Yajat Shamji - How can there be 2 BRILLIAthon stars?

A Former Brilliant Member - 10 months, 3 weeks ago

Mistake: e = 1 e^- = -1 , not e = 1 e^- = 1 , @Jeff Giff

Yajat Shamji - 11 months ago

Yajat’s BONUS \text{Yajat's BONUS}

According to @Jeff Giff's solution, a proton has two 'up' quarks and one 'down' quark, so it must have a total charge of + 2 3 + + 2 3 + 1 3 = + 1 \frac{+2}{3} + \frac{+2}{3} + \frac{-1}{3} = +1

Frisk Dreemurr - 11 months ago
David Vreken
Jul 17, 2020

In Chemistry, p + p^+ represents a proton which has a charge of + 1 e +1 e (where e = 1.60217662 × 1 0 19 e = 1.60217662 × 10^{-19} coulombs), and e e^- represents an electron which has a charge of 1 e -1 e .

Therefore, ( p + ) + ( e ) = ( + 1 e ) + ( 1 e ) = 0 (p^+) + (e^-) = (+1 e) + (-1 e) = \boxed{0} .

LaTeX: 20 20

Intelligible Solution: 10 10

Uniqueness: 10 10

Algorithmic Structure: 3 3

Pics: 0 0

Animations: 0 0

Total: 43 43

Awarded 'BRILLIAthon Star' title for Problem 1 1

Yajat Shamji - 10 months, 3 weeks ago

Fact: It is verified from a lot of experiments, that a proton and electron have an equal charge but opposite in magnitude.

Convention: Conventionally, electron's charge is taken as -1 thus proton's charge would be +1

  • Thus, adding the charges algebraically, we find the answer as follows:

p + + e \boxed{{ p }^{ + }+e^{ - }}

= 1 + ( 1 ) \boxed{=1+(-1)}

= 1 1 \boxed{=1-1}

0 \boxed{0}

@Yajat Shamji - There's some kind of bug, so ignore the lines after proton + electron = hydrogen in bonus info and gimme scores

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LaTeX: 0 0

Intelligible Solution: 10 10

Uniqueness: 10 10

Pics: 1 1

Algorithmic Structure: 3 3

Animations: 1 1

Total: 35 35

Yajat Shamji - 10 months, 3 weeks ago

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What's with the Latex? @Yajat Shamji

A Former Brilliant Member - 10 months, 3 weeks ago

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@A Former Brilliant Member I don't see it!

Yajat Shamji - 10 months, 3 weeks ago

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@Yajat Shamji Its the bug, I see it, I'll send you a pic, wait @Yajat Shamji

A Former Brilliant Member - 10 months, 3 weeks ago

For @Percy Jackson

Yajat Shamji - 10 months, 3 weeks ago

@Yajat Shamji I am done.

Siddharth Chakravarty - 11 months ago

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LaTeX: 19 19

Intelligible Solution: 10 10

Uniqueness: 10 10

Pics: 1 1

Algorithmic Structure: 3 3

Animations: 0 0

Total: 43 43

Awarded 'BRILLIAthon Star' for Problem 1 1 .

Yajat Shamji - 10 months, 3 weeks ago

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Please upload a new problem as problem 2 because the current one has an ambiguous answer.

Siddharth Chakravarty - 10 months, 3 weeks ago

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@Siddharth Chakravarty I can, but I have placed the points on the leaderboard...

Yajat Shamji - 10 months, 3 weeks ago

Basic Info - \textbf{Basic Info - }

A p r o t o n \color{#3D99F6}proton has + v e \color{#3D99F6}+ve charge, while an e l e c t r o n \color{#D61F06}electron has v e \color{#D61F06}-ve charge

\hspace{1cm}

Using info to find answer \textbf{Using info to find answer}

When we add 1 and -1, we get 0, in the same way - adding a p o s i t i v e \color{#3D99F6}positive charge to a n e g a t i v e \color{#D61F06}negative charge results in n e u t r a l \color{grey}neutral charge = 0

\hspace{1cm}

Charge Visualization - \textbf{Charge Visualization -}

This is how electron moves in a hydrogen atom(around the proton) - \textbf{This is how electron moves in a hydrogen atom(around the proton) -}

\hspace{1cm}

Bonus Info - \textbf{Bonus Info - }

A proton and an electron make a hydrogen atom.

A proton has 2 up quarks (u^{\frac{+2}{3}}\​) and a down quark (d^{\frac{-1}{3}}\​), which add up to +1 charge

Yajat Shamji - I'm not done yet, don't gimme scores, I'm sleepy

@Yajat Shamji - what is 2:50 in US time , because I think i'll be asleep then...............

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According to Washington D.C, 09 : 50 09:50 am

Yajat Shamji - 11 months ago

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Dammit! I'll be asleep @Yajat Shamji

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@A Former Brilliant Member Don't worry - the commentary will sum it up (puns included) - comes out at 10 10 am - everybody can read it when they're ready.

Yajat Shamji - 11 months ago

@Percy Jackson , your LaTeX \LaTeX in the last line is flipping. You better fix that!

Frisk Dreemurr - 11 months ago

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Nice pointing out (since I am a LaTeX police officer, LOL, XD)

Yajat Shamji - 11 months ago

I'm sleep deprived (Can't think without sleep), so if you don't SHUT UP I will bring riptide and murder you @Hamza Anushath

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Don't use 'shut up' - I account that as a swear word!

Also, I may remove you from the competition if this continues.

Yajat Shamji - 11 months ago

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Yaj, if you said that cuz you care 'bout me, I'll say you

I can handle this, it's nothin' offensive to me

I learn to take everything in a cool way, not take offence

@Yajat Shamji , @Percy Jackson

Frisk Dreemurr - 11 months ago

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@Frisk Dreemurr @Hamza Anushath - Its hard to enjoy practical jokes when your whole life seems like one - story of my life , its a percy jackson quote

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@A Former Brilliant Member Well, you sure seem to enjoy them nonetheless, don't you?

Frisk Dreemurr - 11 months ago

Ok, sorry, but I'm kinda annoyed

Hahaha, alright, go to bed

"Tucks @Percy Jackson to sleep"

Frisk Dreemurr - 11 months ago

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Don't - you'll aggravate the situation.

Yajat Shamji - 11 months ago

LaTeX wrapping?

Yajat Shamji - 11 months ago

Do you want me to remove you both from the competition, @Hamza Anushath , @Percy Jackson !

Yajat Shamji - 11 months ago

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???

Why suddenly?

What crime have I done?

Frisk Dreemurr - 11 months ago

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I have read all of the comments (I was just reading about Havertz to Chelsea whilst you exchanged the comments) and I have decided enough is enough. Give me an answer within the next minute or I will remove both of you.

Yajat Shamji - 11 months ago

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@Yajat Shamji

N o ? \color{#20A900}\text{N}\color{#D61F06}\text{o}\color{#3D99F6}\text{?} @Yajat Shamji ? \color{#3D99F6}\text{?}

Frisk Dreemurr - 11 months ago

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@Frisk Dreemurr Then behave!

Yajat Shamji - 11 months ago

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@Yajat Shamji Alright...

Frisk Dreemurr - 11 months ago
Frisk Dreemurr
Jul 17, 2020

As protons have positive charge and electrons have negative charges, when their values are equal in an atom, it becomes neutral (i.e. 0 0 )

Same thing goes with static charges, positive plus negative results in a neutral

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LaTeX: 2 2

Algorithmic structure: 3 3

Intelligible Solution: 10 10

Uniqueness: 1 1

Pictures: 0 0

Animations: 0 0

Total: 15 15

Yajat Shamji - 11 months ago

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Woah, I didn't know about this? (I am talking about the marking point scheme)

If I post pictures later, will I get the points for them @Yajat Shamji

Frisk Dreemurr - 11 months ago

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@Frisk Dreemurr Yes. After 2 : 50 2:50 pm, no more editing (see the official page for update).

Yajat Shamji - 11 months ago

Why uniqueness and LaTeX \LaTeX is quite low for my solution @Yajat Shamji ?

Frisk Dreemurr - 11 months ago

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@Frisk Dreemurr How you used the LaTeX is quite simple. And your solution is what most people would say.

Yajat Shamji - 11 months ago

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@Yajat Shamji You are right @Yajat Shamji

Frisk Dreemurr - 11 months ago

Sorry! (For grading of Jeff's solution)

Yajat Shamji - 11 months ago

I give a challenge: can anybody prove that 2 2 up quarks and 1 1 down quark equals 1 1 using mathematical working out in their solution (if they use it)?

@Jeff Giff , @Hamza Anushath , @Percy Jackson

Yajat Shamji - 11 months ago

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@Yajat Shamji , I am not sure, but I think it is because 2 1 = 1 2 - 1 = 1 ?

I dunno, I am just sayin'

Frisk Dreemurr - 11 months ago

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No. That's not it.

Yajat Shamji - 11 months ago

According to @Jeff Giff 's solution, a proton has two 'up' quarks and one 'down' quark, so it must have a total charge of + 2 3 + + 2 3 + 1 3 = + 1 \frac{+2}{3} + \frac{+2}{3} + \frac{-1}{3} = +1

@Yajat Shamji

Frisk Dreemurr - 11 months ago

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Great! I wonder if @Jeff Giff could add that...

Yajat Shamji - 11 months ago

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@Yajat Shamji No problem :)

Jeff Giff - 11 months ago

@Yajat Shamji Could you give me three points as a request (due to help to a competitor...)

Frisk Dreemurr - 11 months ago

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@Frisk Dreemurr I'll think about it...

Yajat Shamji - 11 months ago

The challenge was to help @Jeff Giff , not post it in your own solution! @Hamza Anushath

Yajat Shamji - 11 months ago

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Oh, ok

I'll remove it, k?

Frisk Dreemurr - 11 months ago

3 pending reports

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