tan ( x ) ≈ 0 . 2 r
Find x .
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LaTeX: 2 0
Intelligible Solution: 1 0
Uniqueness: 1 0
Algorithmic Structure: 3
Pics: 1
Animations: 0
Total: 4 4
Awarded 'BRILLIAthon Star' for Problem 5
tan ( x ) x x x ≈ 0 . 2 ≈ tan − 1 ( 0 . 2 ) ≈ 0 . 1 9 7 3 9 ≈ 0 . 2
(This is all true assuming we were calculating in radians)
Do you want me to give you the scores, or not?
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Nah, not really, I just posted a solution as it is a normal problem now
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Do you want to see it though, if you participated?
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@Yajat Shamji – Fine, if you're so obsessed with it..........
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@A Former Brilliant Member – LaTeX: 2 0
Intelligible Solution: 1 0
Uniqueness: 1 0
Algorithmic Structure: 3
Pics: 0
Animations: 0
Total: 4 3
You would've been awarded 'BRILLIAthon Star' for Problem 5 and your total points would've been 1 1 1 + 4 3 = 1 5 4 , 1 0 points behind @David Vreken .
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@Yajat Shamji – Sleep was still better than this :)
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@A Former Brilliant Member – True, but you would've got 2 nd place and got the chance to shape one of my problems and post a problem for me to attempt...
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@Yajat Shamji – Meh, still sleep
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@A Former Brilliant Member – Can't argue with that - I have insomnia (self-daignosis)...
Just remove that ° symbol, because tangent function gives pure numbers as output. @Yajat Shamji
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@Percy Jackson wanted clarification as he was unsure whether it was degrees or radians, so I said degrees and he requested me to put the degrees symbol up, which I did.
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@Yajat Shamji – Write it tan ( x ) ≈ 0 . 2 as tan function takes angle as input not give it as output
@Zakir Husain - atan of 0.2 degrees = 1.99999188 degrees, while atan of 0.2 radians = 0.197731497 radians, so there is a difference, and clarity is required :)
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@A Former Brilliant Member – I have changed it to radians...
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@Yajat Shamji – Radians is not given in superscript, just written normally @Yajat Shamji
@A Former Brilliant Member – What I'm saying is this- tan function gives pure numbers as output for example :
We say that tan ( 3 0 ° ) = 0 . 5 , 0 . 5 is a pure number you can't write it like this tan ( 3 0 ° ) = 0 . 5 ° or tan ( 3 0 ° ) = 0 . 5 r a d
You have to write tan ( x ) ≈ 0 . 2 nothing more is required.
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Graphing y = tan x and y = 0 . 2 and finding the intersection for 0 < x < π gives an x -value of x ≈ 0 . 1 9 7 .