d x d ( sin x cos x tan x csc x sec x cot x ) = ?
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The problem would be much better posed as an MCQ, instead of an integer answer.
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Oh, thank you for your advice I would do it in future. I cant change can you please do that for me? Thanks!
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Sure, done.
How can we solve d x d sin − 1 x cos − 1 x tan − 1 x csc − 1 x sec − 1 x cot − 1 x ?
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It'll be the same right?
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Nono Abhiram, sin^-1 is not the same as 1/sin . Same for others ;)
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@Ashish Menon – Is that so?
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@Abhiram Rao – Yes cosec and arcsin are different as far as I know.
I dont think that this function is differentiable as it is not continous . it is defined only for x=1,x=-1 as domain of arcsin( x) is [-1,1] and domain of arccosec( x) is[1,infinity)U(-infinity,-1] Please correct me if I am wrong.
0 is not one of the given solutions among the multiple choice answers. 1 is, which is incorrect but is accepted as the correct answer.
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Ah, that's my fault as I was editing the options. Fixed it, thanks!
sin is canceled by csc; cos is canceled by sec; tan canceled by cot. 1 is what's left. Derive 1 = 0
That's right. The function expression is equal to 1, except at points where either sin x or cos x is equal to zero. Keep in mind that the function does not exist at these points, and its derivative will not exist at these points either.
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d x d sin x cos x tan x csc x sec x cot x = d x d 1 = 0
Applying product rule would prove tedious.