Calculate the equivalent resistance in this circuit ...

According to the image , What is the equivalent resistance ?

2 Ω 20 Ω 12 Ω 8 Ω

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5 solutions

Name the junctions A, B, C and D Now you can note that as the junction A and C is shorted they are one and the same Similarly the junctions B and D will be one and the same as they are shorted

Now redraw the diagram considering only the junctions A and B

You can notice that the resultant diagram will be in the form of three resistors in a parallel circuit

Then effective resistance of resistors in Parallel is given by 1/Rs=1/R1 + 1/R2 + 1/R3

On solving using R1=8ohm R2=4ohm and R3=8ohm The value of Rs will be 2ohm

they are in series R1 + R2 + R3 = Req ?????

Taha Ali - 6 years, 8 months ago

They aren't in parallel... The shortening logic is incorrect... Study the picture carefully

Ranjit Abraham - 6 years, 8 months ago

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yes they are parallel

Arko Pal - 6 years, 8 months ago

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Can you tell us that how they are parallel ?

Taha Ali - 6 years, 7 months ago

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@Taha Ali Becz 3ragistance are attached with both terminal

Farman ansari - 6 years, 1 month ago
Rajen Kapur
Nov 1, 2014

No calculations required. As they are in parallel first 8 in parallel with 8 gives equivalent resistance 4 which again in parallel with 4 gives 2 as final answer.

The current in the circuit will follow the non-resistance path above the 8 and 4 ohm resistor and will only encounter the last 8 ohm resistor . So the equivalent resistance will be 8 ohm

Rishab Tibrewal - 6 years, 6 months ago

rishab is right, if current flows to the circuit, the current prefer to flow in non-resistive line. so, the Req is 8 ohms

Faris Zain - 6 years, 1 month ago
Mahesh Vmtw
Sep 18, 2014

here by rearranging the network ,3 resistors are in parallel so by using formula we can solve

i think the answer is wrong these are not in parallel but htere is another way to solve this

Aditya Gaur - 6 years, 8 months ago

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what is your another way to solve this ?

Ahmed Salah - 6 years, 8 months ago

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Current tends to follow the path of slightest resistance. So, whichever point be the input point of the current, it'll take the short circuit path & reach the final resistor. so the resistance it would face is 8 ohm. That's what I can see, please point out, if I'm wrong.

sameen tz - 6 years, 8 months ago

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@Sameen Tz That's what I was seeing, to me too 8 appears to be the answer as the current will take the path of least resistance and in both the first and third junction easy paths are available...

yogesh singh - 6 years, 8 months ago

short circuit route way, only 8ohm is active, i think

Loki Kitel - 6 years, 8 months ago

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@Loki Kitel Yes you are right Loki

Rishab Tibrewal - 6 years, 6 months ago

i will tell you

Aditya Gaur - 5 years, 11 months ago

Yes, they ain't in parallel!

raul tripathi - 6 years, 8 months ago

These are in parellal

Farman ansari - 6 years, 1 month ago

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get lost in the woods

Aditya Gaur - 6 years ago

abey 6 question solve kiya hain and i have solved 401

Aditya Gaur - 5 years, 10 months ago

All are in parallel

Leonardo Wilhelm - 6 years, 8 months ago
Lu Chee Ket
Oct 26, 2015

With the 4 ohm removed, the 8 ohms are just in parallel as 4 ohms. Any added connection must make a smaller resistance; further, the 4 ohm resistor crossing the parallel is in parallel with the resultant 4 ohm again. As a result, two 4 ohms in parallel make 2 ohms as a whole. No complicated situation involved.

David Rubinstein
May 5, 2015

No Current will go through the 4. End up with 2 8's in parallel and so answer is 4

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