Consider I n = ∫ 0 2 π ( ln sin x ) n d x , where n ∈ N .
∫ 0 2 π ln sin x d x ≈ − 1 . 0 8 7 9 ∫ 0 2 π ( ln sin x ) 2 d x ≈ 2 . 0 4 6 6 ∫ 0 2 π ( ln sin x ) 3 d x ≈ − 6 . 0 4 1 8 ∫ 0 2 π ( ln sin x ) 4 d x ≈ 2 4 . 0 5 2 9
As you can see, ⌊ ∣ I n ∣ ⌋ is always equal to or close to n ! . For what first value of n , ⌊ ∣ I n ∣ ⌋ stops being equal to n ! ?
Bonus: Can you explain why this pattern follows?
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@Digvijay Singh Do you have a rigorous proof??? I only checked numerically.........
Hmm, can't remember when i posted it.
It's a stupid problem anyway. I'm deleting it.
Hey, what report did you post on the other problem and what was the problem (because it seems to be deleted)?
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No don't delete it!! It's a real cool pattern!! And ohhh!! I'm sorry.......I have already deleted that report.....I just did that to see whether I was missing some important information mentioned by someone else in the reports section........
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How did the problem get deleted? I didn't delete it.
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@Digvijay Singh – Wut??? That's weird.......When I reported the problem, it was already deleted......That is mainly the reason why I reported the problem in the first place, to check if I had missed something......
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@Aaghaz Mahajan – What was the problem about? I don't remember it.
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@Digvijay Singh – IDK......Basically, I saw the title of this problem as Calculus and Patterns 2....So, I thought there must be a part 1 and I simply removed the 2 from the web address and I was directed to this link..........As you can see, the problem was already deleted.....
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@Aaghaz Mahajan – Oh i remember it now, it was a pattern i saw in integrals of type ∫ 1 e ( ln x ) n d x .
I deleted it for unknown reasons (i don't really remember why :p)
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@Digvijay Singh – xD!! But don't delete this one......!! I think there MIGHT be something more in this problem than what meets the eye......Btw, how is JEE prep going on??
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@Aaghaz Mahajan – I'm doing fine.. and i hope you do great too.. I'm going offline. Take care :)
Hey, the other problem is available here
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Not a full solution.
You end up with that sum and it's pretty easy to see why it is close to n!