Can you do your addition?

$2013+2014+2015$ $=(2014-1)+2014+(2014+1)$ $=2014-1+2014+2014+1$ $=2014+2014+2014-1+1$ $=3\times 2014$ $=\boxed{6042}.$

sum of numbers = middle number × total numbers

= 2014 × 3 = 6042

GOSH!

$2013$ = $2*10^3+0+1*10+3$

$2013$ = $2*10^3+0+1*10+3$

$2013$ = $2*10^3+0+1*10+3$

Adding them together, $2013+2014+2015$ is equal to $10^3(2+2+2)+10^2(0+0+0)+10(1+1+1)+10^0(3+4+5)$ , which is, in turn, equal to $\boxed {6042}$ . $\LARGE :D$

just add people i guess it is'nt that hard ans = 6042

Just add the numbers no tricks 2013 + 2014 = 4027 and 4027 + 2015 = 6042

All I did was express everything in terms of the number 2013. Then, just use a property of distribution, and you're done! :)

$2013+2014+2015$

$2013+(2013+1)+2015$

$2013+(2013+1)+(2013+2)$

$2013+2013+2013+1+2$

$3(2013)+1+2$

$3(2013)+3$

$3(2013)+3(1)$

$3(2013+1)$

$3(2014)$

$6042$

$\begin{aligned} 2013 + 2014 + 2015 & = 3×2014\\ & = \color{#69047E}{\boxed{6042}} \end{aligned}$

In general $n+(n+1)+(n+2)=3n+3=3(n+1)$ .The question fits this form(which means that $2014=n+1$ ) so setting $2014$ in the L.H.S of equation,we get $3(2014)=\boxed{6042}$

$Simple\quad mathod\\ 2013+2014+2015\\ =2014+2014+2014\\ =6042$

let x be 2013 then x+x+1+x+2 =3x+3 =3*2013+3 =6039+3 =6042

2013+2014+2015=\ 2010+2010+2020=6040\ 6040+3=6043\ 6043+4=6047\ 6047-5=6042\ 2013+2014+2015=6042