A solid has 12 faces and 20 edges. Given that Euler's Formula applies, how many vertices does it have?
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12 faces but only 10 vertices? What in the world would the solid look like?
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Pentagonal anti-prism.
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Isn't it just 7 faces?
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@Saya Suka – Sorry, meant to write pentagonal anti-prism. Autocorrect must've done something dodgy.
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@Sharky Kesa – Did some digging and they said it is also called half isosceles icosahedron (2).
The best I can imagine is 12 faces with 8 vertices.
it will have 2 pentagonal faces and 10 triangular faces >v<
Please explain in full with a diagram
We can use the formula V − E + F = 2 where V is the number of vertices, E is the number of edges and F is the number of faces.
Entering the known quantities, we get
V − 2 0 + 1 2 = 2
V = 2 + 2 0 − 1 2
V = 1 0
V-E+F = 2, where E = 20, F = 12, then substitute, V - 20 + 12 = 2, so, V = 10
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Euler's Formula states that f + v − 2 = e where f is the number of faces, v is the number of vertices and e is the number of edges.
If we enter the known values into the equation we get
1 2 + v − 2 = 2 0
Solving the equation, we get the value of v as 10.