If the capacitor is initially uncharged, then how much current (in ) flows through the circuit just after the switch is closed?
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Just after the switch is closed, the capacitor has no charge so it behaves as plain wire, i.e. potential difference across it is 0. We can apply ohm's law across the resistor.
V = I R
The potential difference across the resistor is 6 V . The resistance of the resistor is 4 Ω . Therefore the current flowing through resistor, and hence through the circuit is I = R V = 4 6 = 1 . 5 A.
To convert Ampere to milliAmpere, we must multiply by 1000. Thus the current flowing through the circuit just after the switch is closed is 1 5 0 0 mA □