Changing Gears

When a person pushes on the pedals of a bicycle, the pedals turn the front gear, the front gear pushes on the chain, the chain turns the back gear and the back gear turns the rear wheel.

In some cycles, it is possible to change the diameters of the front gear as well as the back gear. The cyclist can adjust the sizes of the gears to change the amount of force required to pedal.

A cyclist, who is riding uphill, wants to minimize the amount of force required. Which combination of gears will require the least force?

Small front, Large back Large front, Small back Small front, Small back Large front, Large back

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1 solution

Pranshu Gaba
Mar 11, 2017

Let r p r_p be the distance of pedal from its axis, r f r_f be the radius of front gear, r b r_b be the radius of back gear, and r w r_w be the radius of the back wheel.

Suppose we apply a force of F p F_p on the pedal. Then the torque on the front gear is τ f = F p r p \tau_f = F_pr_p . The force in the chain due to this is F c = τ f r f = r p r f F p F_c = \dfrac{\tau_f}{r_f} = \dfrac{r_p}{r_f}F_p .

The chain applies a torque of τ b = F c r b = r p r b r f F p \tau_b = F_c r_b = \dfrac{r_pr_b}{r_f}F_p on the back wheel. This torque is balanced by the torque due to static friction between the wheel and the ground (assuming the wheel does not slip). We get

F d = r p r b r f r w F p F_d = \dfrac{r_pr_b}{r_fr_w} F_p

Here, F d F_d is called the driving force. It is provided by static friction between the wheel and the ground. It is the external force on the cycle which pushes it forward.

The values r p r_p and r w r_w are fixed in a given cycle, so for a given F d F_d , the value of r b r f F p \dfrac{r_b}{r_f} F_p is also fixed. Therefore F p F_p is directly proportional to r f r b \dfrac{r_f}{r_b} . To decrease F p F_p , the amount of force required to pedal, we should decrease r f / r b r_f/r_b . We can cause the maximum decrease in r f / r b r_f/r_b if we decrease the radius of the front gear and increase radius of the back gear.

This gear configuration is called low gear, because it requires the least amount of force to pedal, and also because each full turn of the pedal results in a smaller distance moved by the cycle. If we increase the gear ratio r f / r b r_f/ r_b by using a larger front gear and/or smaller back gear, then the configuration is called high gear. It requires more force to pedal, but each turn of the pedal results in greater forward motion by the cycle.

How did you find the force in chain?

Jatin Sharma - 4 years ago

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If we assume the front gear to be rotating at constant speed, then the net torque on it should be zero. This condition gives us F c r f = F p r p F_c r_f = F_p r_p .

Pranshu Gaba - 4 years ago

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aren't you forgetting that there are two Fc acting on the front gear?

Jatin Sharma - 4 years ago

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@Jatin Sharma Yes, good catch. There are two F c F_c on the front gear. F c F_c is still proportional to r p r_p , that doesn't change.

Pranshu Gaba - 4 years ago

the lower part of the string has tension too right? Now that i think of it, i could be wrong ._. But if it is infact = 0 Then how do you prove that?

Jatin Sharma - 4 years ago

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