Chess puzzle of a different sort
Is it possible to remove 2 pieces from the board in a single turn whilst playing with the standard rules of chess?
Clarification: Remove means taken off the board, not move two pieces simultaneously. The problem refers to the literal physical pieces; additionally, if a physical piece is placed on the board, that is considered a different operation.
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4 solutions
very innovative
Cunning problem!
Technically, you're not removing 2 with the proposed solution. You're removing 1 (the other side's), and you're replacing your own...
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You removed the others, you removed one of your own, and you add a new piece...
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Promotion is not removal. The promoted piece is in the same place that it was before promotion and has a new role. I think this problem needs to be rephrased.
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I'd rather not... Sorry, but my email is personal.
Isn't it possible when the game ends. That is suppose you kill one piece of opponent which then leads to checkmate! Two pieces have been removed.
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One the piece you killed and then the King.
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But you don't remove the King from the board. You simply say checkmate.
@Thomas Raffill I agree.
If you have a lieutenant, and give him a promotion to general. Do you remove him or match his abilities to his achievements?
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Uh, what? This is chess...
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I tried to express, the logic if you tried to follow the moves back. So that the chess piece that replaces it, is just an different state of the same piece. Because, i see every pawn as a potential queen. Like superpositioning.
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@Cnarfeł Anioł – No, this is a physical game of chess (as I have mentioned in the question). Whenever playing with a real board with real pieces, upon promotion, you remove the pawn and put the promoted piece on instead.
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@Sharky Kesa – But if we are counting physical removals from the board, then any capture would work. We first lift the capturing piece from its original position (removal number 1), then put it back down again on the target square, and finally we remove the captured piece (removal number 2). I really think this problem needs to be phrased more carefully.
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@Thomas Raffill – Moving a piece is not the same as removing from the board.
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@Sharky Kesa – When you move a piece, you first physically remove it from the board before putting it down again. I don't think it's clear from the problem description that it doesn't count.
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@Thomas Raffill – No, you move this piece, not remove it. The act of removal implies it is taken off the board permanently.
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@Sharky Kesa – To remove a piece and put it back does not count for you, but to remove a piece and put it back in its new promoted state does count for you. And that detail, which is not given in the problem description, is crucial for solving it. That's why I say the problem description is not clear.
that is very stupid think of it 1 move 2 actions
Isn't it easier? If my horse happened to jump your horse both will be removed? 2 pieces gone
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No, if a knight kills another knight, both knights aren't removed. Only the attacked knight is removed.
If you capture your opponents piece then you have moved your piece as well as the piece you captured to take it off the board. That's two pieces that you have now moved.
I said removed, not moved.
if i kill my opponents piece than my piece has also been moved.
so, there has been 2 moves.
You have to remove 2 pieces from the board, not move two pieces. This solution is invalid.
How about when the pawn does en passant?
No, only one pawn is taken, the other pawn stays on the board. It is also impossible for the pawn to do a normal capture as well as an en passant since the pawn being en-passant-ed has moved 2 squares forward in the previous move.
That's true
If a pawn moves to the back ranks, whilst killing another piece, you must remove the piece killed as well as the pawn so it can be promoted. You have removed 2 pieces!