A man bumps into his mathematician friend on the street that he hasn't seen in 5 years. The man asks the mathematician how old his children are. The mathematician who always replies in riddles said "I now have three children. The sum of their ages is equal to the number of windows on the building in front of you and the product of their ages equals 36." The friend then says "I need one more piece of information." The mathematician then replies "My youngest child has blue eyes." What is the number of windows in that building
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Let the three children's ages be a , b , c where a b c = 3 6 . a + b + c = no. of windows. This number of windows seen must have more than one possibility of a , b , c values satisfying a b c = 3 6 such that the man has to ask for another piece of information.In fact, for one of the possibilities, there must be two smallest values and for the other possibility, there must be exactly one smallest value such that there is a youngest child. The answer is 1 3 such that the 2 possibilities are ( a , b , c ) = ( 9 , 2 , 2 ) and ( a , b , c ) = ( 6 , 6 , 1 )