Circle
Two identical circles intersect so that their centres and the points at which they intersect forms a square of side 1 cm.The area in sq.cm of the portion that is common to the two circles ?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
Same method!
Log in to reply
nice @Vinayak Srivastava , @Foolish Learner . have you done my another problem this
Log in to reply
I was watching it, I want a clarification, does the equation contain a c or not?
Log in to reply
@Vinayak Srivastava – no,if it was then it was easy
Log in to reply
@Srijan Singh – Ok, I was thinking there was a typo. Thanks!
Log in to reply
@Vinayak Srivastava – if you get right,post the solution
Log in to reply
@Srijan Singh – if you have not done yet , can I POST the solution
You have messed up somewhere in that problem. There are many answers to that problem. For example, a = 1 , b = 1 2 , c = 3 9 ; a = 2 , b = 1 2 , c = 2 6 , so on.
@Foolish Learner TRY this
Area of common region between the two circles is
2 × (area of one of the circular sectors subtending angle 2 π at the centre of the corresponding circle -area of the isosceles right triangle formed with the two radii of that circle and the common chord)
= 2 ( 2 1 × 1 2 × 2 π − 2 1 )
= 2 π − 1 .