Circles are cool!

Geometry Level 2

Consider two parallel chords of a circle A B AB and C D CD where A B AB is a diameter.It is known that A C = 13 AC=13 and A D = 84 AD=84 .Find the radius of the circle.


The answer is 42.5.

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1 solution

If the two chords A B AB and C D CD are parallel to the x x -axis, then they are symmetrical along the y y -axis through the origin of the circle. Due to the symmetry, B D = A C = 13 BD = AC = 13 . Since A B AB is a diameter, A D B = 9 0 \angle ADB=90^\circ . Therefore the diameter of the circle D = 1 3 2 + 8 4 2 = 85 D = \sqrt{13^2+84^2} = 85 and the radius r = 42.5 r=\boxed {42.5} .

I still do not know why that angle is 90 degrees? I cannot justify it?

Adam Staples - 6 years, 6 months ago

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Sorry, I didn't explain it. Angle in a semicircle is always 9 0 90^\circ . Since A B AB is a diameter and D D is on the circumference, therefore, A D B = 9 0 \angle ADB = 90^\circ .

Chew-Seong Cheong - 6 years, 6 months ago

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Thanks, I did not know that! http://www.savory.de/maths18.htm I found an amazing proof here for anyone interested!

Adam Staples - 6 years, 6 months ago

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@Adam Staples That proof is available in 9th standard maths.

Dheeraj Dhillon - 5 years, 5 months ago

Angle in front of Diameter is 90° according to circle properties.

Azeem Haïder - 5 years, 9 months ago

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