Clockwork

Algebra Level 3

How many minutes is it before 1p.m. if 20 minutes ago it was three times as many minutes past 11 a.m.?

35 minutes 25 minutes 15 minutes 30 minutes

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1 solution

Jakub Samoraj
Sep 11, 2015

1 p.m. less 25 minutes = 12.35

12.35 less 20 minutes = 12.15

12.15 less 75 minutes (3 x 25) = 11 a.m.

Can you elaborate more pleas !

How you got 25, and 75 ? Why you are multiplying 3 x 25 ? Why you are subtracting 25 minutes from 1 p.m. Thank you Your solution will be brilliant if you explain a little more :D \begin{array}{|cc|} \hline \text{How you got 25, and 75 ?}\\ \text{Why you are multiplying 3 x 25 ?}\\ \text{ Why you are subtracting 25 minutes from 1 p.m.}\\ \text{Thank you}\\ \text{Your solution will be brilliant if you explain a little more :D}\\ \hline \end{array}

Syed Baqir - 5 years, 9 months ago

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Hello Syed, thank you for your request. I hope I can help you. I can give you a hint, in order to resolve this problem you have to try to estimate what time is it at the moment. You may presume that it is past twelve o' clock, but how much exactly? 20 Minutes ago it was three times as many minutes past 11 a.m., so you may infer that the present time minus one third of an hour. So, you have to find 25 minutes as a proportion of the time from 11 a.m. and make the 25 minutes an unknown variable as a proportion of that time. You know that this time has to be divided into three parts. Please carry on to resolve this task if you love Mathematics just as me! Best wishes with everything!

Jakub Samoraj - 5 years, 9 months ago

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Thank you :D

K e e p i t u p ! \color{#D61F06}{Keep \ it \ up !}

Syed Baqir - 5 years, 9 months ago

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@Syed Baqir 👌👍💡 Good luck!

Jakub Samoraj - 5 years, 9 months ago

I think I got your question until here :

Let presume time now = T

Therefore, T - 20 = 3(x) + 11:00

Let assume: 11:00 < T < 1:00 pm => 2 Hours

Syed Baqir - 5 years, 9 months ago

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