Cody's Awesome Balloons -2

$\bullet$ Total upward force is $\displaystyle \sum_{k=-3} ^\infty 10^{-k} =1000+100+10+1+0.1+... =1111.\overline{1}N$ .

$\bullet$ As balloons are massless, there is only 1 force acting downwards and it is weight of Cody, which is $54.4\times g$ .

So the net force acting is $(1111.\ - 54.4\times g)N$ is upward direction.

---

$\bullet$ Acceleration is given by $\overline{F}=m\overline{a}\implies \overline{a}=\dfrac{\overline{F}}{m} = \dfrac{1111.\overline{1} -54.4\times g}{54.4} m/s^2\\ \therefore \overline{a} = \Bigl( \dfrac{1111.\overline{1}}{54.4} -g \Bigr) m/s^2$ in upward direction.

$a\approx 20.424836601307188 - 10 \approx \boxed{10.425} m/s^2$

downward force is

f=mg = 54.4 (10) =544 N

upward force is

f1=1111.11 N

{use sum to infinite terms of an GP}

now ,

f1 - f

=1111.11-544

=567.11

WKT,

g= F/m

=567.11/54.4

= 10.425

You and cody both are awsome really

this question was easy..as it's former part...but when i was entering the answer(10.5) the connection became slow, and i came out, only to later put this answer in part-1....-_-(f * *d). But anyway this part was right. It can be found as total acceleration=(1111.11111....-544)/544=10.4 or 10.5 something