Collision in Spring-mass System-1!

Two bodies A A and B B of mass m m and 2 m 2m respectively are placed on a smooth floor. They are connected by a spring of negligible mass. A third body C C of mass m m is placed on the floor. The body C C moves with a velocity v 0 v_0 along the line joining A A and B B and collides elastically with A A . At a certain time after the collision it is found that the instantaneous velocities of A A and B B are same and the compression of the spring is x 0 x_0 . The spring constant k k will be :

m v 0 2 x 0 \large \frac{mv_0}{2x_0} m ( v 0 x 0 ) 2 \large m (\frac{v_0}{x_0})^2 2 3 m ( v 0 x 0 ) 2 \large \frac{2}{3} m (\frac{v_0}{x_0})^2 2 m v 0 x 0 \large \frac{2mv_0}{x_0} None of These

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2 solutions

Nishant Rai
May 27, 2015


Note: Since the colliding bodies C C & A A are of the same mass m m , and they collide elastically, so their velocities after collision are exchanged.

Please explain the conservation on energy equatiom in brief.... I didn't get that!!😢

Akhil Bansal - 5 years, 9 months ago
Kyle Finch
May 27, 2015

Using conservation of momentum.

m v o = 3 m v mv_{o}=3mv where v is instantaneous velocity.

Using conservation of energy

0.5 m v o 2 = 0.5 × 3 m v 2 + 0.5 k x o 2 0.5mv_{o}^{2}=0.5\times 3mv^2 +0.5kx_{o}^2

Did i do correctly @Nishant Rai

Kyle Finch - 6 years ago

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yes, but please do write how you got those 2 equations, i mean by using COLM and COE.

@Kyle Finch

Nishant Rai - 6 years ago

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Can u post the solution for the elctric field one u recently posted

Kyle Finch - 6 years ago

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@Kyle Finch check it out.

@Kyle Finch

Nishant Rai - 6 years ago

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