Columnar Addition?

0. 1 2 3 1 2 3 1 + 0. 0 1 2 3 1 2 3 0. 1 3 5 4 3 5 4 \large{\begin{array}{cccccccc} &0 .& 1 & 2& 3 & 1&2& 3 & 1&\ldots\\ +&0. & 0 & 1& 2 & 3&1& 2 & 3&\ldots\\ \hline &0. &1 &3 &5& 4 & 3&5&4&\ldots\\ \hline \end{array}}

The above shows the sum of the two fractions 123 999 \dfrac{123}{999} and 123 9990 \dfrac{123}{9990} when written in decimal representation.

If 123 999 + 123 9990 = 1 10 + 354 x \dfrac{123}{999} + \dfrac{123}{9990} = \dfrac1{10} + \dfrac{354}x , find the value of x x .


The answer is 9990.

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1 solution

Relevant wiki: Converting Fractions into Decimals

Method 1 \Large\color{#D61F06}{\text{Method 1}}

Let y = 123 999 y=\frac{123}{999} .

y + y 10 = 1 10 + 354 x \Rightarrow y+\dfrac{y}{10}=\dfrac{1}{10}+\dfrac{354}{x}

11 y 1 10 = 354 x \dfrac{11y-1}{10}=\dfrac{354}{x}

x = 10 11 y 1 × 354 x=\dfrac{10}{11y-1}×354

x = 3540 11 × 123 99 1 x=\dfrac{3540}{11×\frac{123}{99}-1}

x = 3540 × 999 354 x=\dfrac{3540×999}{354}

x = 9990 x=\boxed{9990}


Method 2 \Large\color{#D61F06}{\text{Method 2}}

Converting (0.1354354...) into fraction.

Let x = 0.1354354... x=0.1354354...

10 x = 1.354354... \rightarrow 10x=1.354354...

10000 x = 1354.354354... \rightarrow 10000x=1354.354354...

Subtracting these two.

9990 x = 1353 \rightarrow 9990x=1353

0.1354354... = 1353 9990 \Rightarrow 0.1354354... =\dfrac{1353}{9990}

And we know that.

0.123123... + 0.0123123 = 0.1354354... \Rightarrow 0.123123...+0.0123123=0.1354354...

123 999 + 123 9990 = 1353 9990 \Rightarrow \dfrac{123}{999}+\dfrac{123}{9990}=\dfrac{1353}{9990}

1353 9990 = 1 10 + 354 9990 = 1 10 + 354 x \Rightarrow \dfrac{1353}{9990}=\dfrac{1}{10}+\dfrac{354}{9990}=\dfrac{1}{10}+\dfrac{354}{x}

x = 9990 \therefore x=\boxed{9990}

Did you notice that I've already written 9990 in the question? Coincidence?

Pi Han Goh - 5 years, 2 months ago

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Yes!!.......

A Former Brilliant Member - 5 years, 2 months ago

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Can you explain why is it so?

Hint : Geometric progression sum .

Pi Han Goh - 5 years, 2 months ago

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@Pi Han Goh Sorry! I am unable to do it. :-(

I did:

0.123123... = 1.23 + 0.0123 + 0.00123 + . . . = \Rightarrow 0.123123...=1.23+0.0123+0.00123+...= 123 100 1 1 100 \dfrac{\frac{123}{100}}{1-\frac{1}{100}}

Similarly,

0.0123123... = 123 10000 1 10 10000 \Rightarrow 0.0123123...=\dfrac{\frac{123}{10000}}{1-\frac{10}{10000}}

0.1354354... = 1353 10000 1 10 10000 \Rightarrow 0.1354354...=\dfrac{\frac{1353}{10000}}{1-\frac{10}{10000}}

Can you now tell me why is it so?And correct me If I am wrong.

A Former Brilliant Member - 5 years, 2 months ago

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@A Former Brilliant Member You're on the right track. But you made some errors.

Hint : See the big sum that I've written up. Write it as 0.1 + "something else". This "something else" can be written as a geometric progression sum right? Now do you know how to convert a decimal number to a fraction?

Pi Han Goh - 5 years, 2 months ago

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@Pi Han Goh My brain has stopped working.I will do it in morning.Its 1:10 a.m. here.:)

A Former Brilliant Member - 5 years, 2 months ago

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@A Former Brilliant Member Alright, I'll give you one more hint, do try to work on it in the morning!

Write the two fractions given in decimal representation. What is their sum? I've already given it to you, right? Now how do you convert that resultant number back into a fraction?

Pi Han Goh - 5 years, 2 months ago

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@Pi Han Goh Okay.
123 999 + 123 9990 = 1353 9990 \Rightarrow \dfrac{123}{999}+\dfrac{123}{9990}=\dfrac{1353}{9990}

1353 9990 = 1 10 + 354 9990 = 1 10 + 354 x \Rightarrow \dfrac{1353}{9990}=\dfrac{1}{10}+\dfrac{354}{9990}=\dfrac{1}{10}+\dfrac{354}{x}

x = 9990 \therefore x=9990

A Former Brilliant Member - 5 years, 2 months ago

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@A Former Brilliant Member 354 9990 = 0.0354354... \Rightarrow \dfrac{354}{9990}=0.0354354...

Adding 1 10 = 0.1 \dfrac{1}{10}=0.1 results in,

0.0354354... + 0.1 = 0.1354354... \Rightarrow 0.0354354...+0.1=0.1354354...

Which equals to:

0.123123... + 0.0123123... = 0.1354354... \Rightarrow 0.123123...+0.0123123...=0.1354354...

: ) \Large :-)

A Former Brilliant Member - 5 years, 2 months ago

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@A Former Brilliant Member Great work! Can you add it into your solution? Thanks.

Pi Han Goh - 5 years, 2 months ago

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@Pi Han Goh Welcome Sir. I reached here because of your hints. Thank you sir. :)

A Former Brilliant Member - 5 years, 2 months ago

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@A Former Brilliant Member Can you add these workings to your solution?

Pi Han Goh - 5 years, 2 months ago

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@Pi Han Goh Written. Have a view :).

A Former Brilliant Member - 5 years, 2 months ago

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@A Former Brilliant Member Great! Thanks! Did you enjoy this question?

Pi Han Goh - 5 years, 2 months ago

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@Pi Han Goh :).Yes enjoyed it really.Hmm..I want more great questions from you.

A Former Brilliant Member - 5 years, 2 months ago

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@Pi Han Goh OMG!......

A Former Brilliant Member - 5 years, 2 months ago

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