A hollow sphere of radius R of uniform surface charge density σ , its center is placed at origin A .
A hollow hemispherical surface of
R
is at centre
B
(
x
−
2
)
2
+
y
2
+
z
2
=
1
,
x
≥
2
Find the electric flux through the curved surface of that hemisphere due to that hollow uniformly charged sphere.
Details and Assumptions
1)
R
=
1
2)
Coordinates of
A
and
B
are
(
0
,
0
,
0
and
(
2
,
0
,
0
)
respectively.
3)
σ
=
1
4)
Electric permittivity
ϵ
0
=
1
5)
I have provided a two dimensional figure. But this system is in three dimensions. I have provided the view of figure from
−
Y
axis.
6)
The answer is positive.
This problem is original.
This problem is dedicated to my respected teacher Steven Chase
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Amazing! Yeah; the integral Neeraj asked me to solve must have been the wrong one to solve the problem. That's what I thought. A nice numerical solution, sir. I love how numerical methods are so straightforward and dependable upon.
Log in to reply
Thanks. Yeah, the thing I love most about code is that I don't have to bother with big complicated expressions. I can assemble things in small pieces.
Log in to reply
Yes, indeed. I don't enjoy simplifying huge expressions. Did you see how big that integral Neeraj came up with was? Biggest thing I've seen in my life lol. Much easier to do numerically.
Log in to reply
@Krishna Karthik – @Krishna Karthik No matter which method is good and whatever the expression is, the main thing is that Steven Chase is a stud and smart guy.
Log in to reply
@Talulah Riley – Lmao. Well, you have a long way to go. Steven Chase is more than twice as old as you, and I am younger than all of you lol, so boy, I have a long way to go.
I literally just started learning physics and maths and shit 3-4 years ago. I have a lot to do.
Log in to reply
@Krishna Karthik
–
@Krishna Karthik
I have started learning physics just 2 years ago.
And Steven Chase is a smart guy.
Log in to reply
@Talulah Riley – Yeah. I started learning advanced math around three years ago, and physics only 1.5 years ago.
@Talulah Riley – I think I started learning physics back in 2003
Log in to reply
@Steven Chase – Ok, boomer.
Nah jk jk jk jk. Just kidding lmao
@Steven Chase – I was born 2 years after 2003🤣
@Steven Chase – Just wanna know: did you do any physics in High School or anything mathematics related in high school?
Log in to reply
@Krishna Karthik – I took math and physics classes, but didn't do any competitions or anything
Log in to reply
@Steven Chase – Ah, fair enough. Competitions aren't really worth it in my opinion. Most of the people who win them are just Asians.
Log in to reply
@Krishna Karthik
–
@Krishna Karthik
@Steven Chase
,so let's end this discussion with a sentence.
"mention[1247521:Steven Chase] is a smart guy".
Log in to reply
@Talulah Riley – Anyways, I have to go for something lol. See ya!
@Steven Chase
–
@Steven Chase
Do you teach students?
I want to study in your class.
@Steven Chase – @Steven Chase 16 May 2003 is my date of birth.when I was born you started learning physics. Nice.
Log in to reply
@Talulah Riley – Hehe that's funny.
Log in to reply
@Krishna Karthik – @Krishna Karthik what is your date of birth?
Log in to reply
@Talulah Riley – bruh 2005. Can't tell you the month and the day tho, soz
@Talulah Riley – Physics is kinda new to me; I started programming around 2 years ago.
@Steven Chase
Very nice solution.
You are a very smart and intelligent guy.
@Steven Chase
Do you know who is Lil Dougy ??
In the below link it is written your name also. https://www.facebook.com/SchweitzerEngineering/posts/sel-lead-research-engineer-doug-taylor-has-been-selected-to-participate-in-the-n/2205749516118795/
By the way
@Krishna Karthik
share your views
Log in to reply
Yeah; Dougy looks like a subordinate, from what I understand. He likes to help all the new engineers. Cheers for little Dougy! Good on ya, mate!
Log in to reply
@Steven Chase
@Krishna Karthik
like wise he has also helped us
We are also engineers.
mention[1247521:Steven Chase] is really a very smart man.
Yeah bro,Lil Dougy is also amazing.
Log in to reply
@Talulah Riley – Good on ya, Dougo mate!
Log in to reply
@Krishna Karthik
–
@Krishna Karthik
yeah bro, that good bro
Dougy is amazing and good one.
Steven Chase is also a very smart guy. Lol
Yeah, Doug is indeed a good guy
Log in to reply
@Steven Chase – Lmao🤣 "Lil Dougo"
Log in to reply
@Krishna Karthik – @Krishna Karthik why are you laughing so much???
Log in to reply
@Talulah Riley – Just "Dougo" Idk... I just found that so funny
Log in to reply
@Krishna Karthik
–
@Krishna Karthik
because that relates with Dog word .
Be we have to respect them instead of laughing.
Thierr knowledge is very far from you and me.
Log in to reply
@Talulah Riley – True, true. And Aussies just add "o" to any name to make a nickname.
@Steven Chase
–
@Steven Chase
you are also a
v
e
r
y
v
e
r
y
good guy.
Is that photo of you or Lil Dougy?
Log in to reply
@Talulah Riley – @Steven Chase @Neeraj Anand Badgujar Yeah; I also kinda want to know.
Log in to reply
@Krishna Karthik
–
@Krishna Karthik
by the way the photo of that man seems me sexy also.
Share you views bro.?
Log in to reply
@Talulah Riley – What? Are you gay? I didn't think you were gay.
Log in to reply
@Krishna Karthik
–
@Krishna Karthik
I am not a gay.
Why are you saying this???
Log in to reply
@Talulah Riley – 'cause you said that photo of the man seems "sexy" Sorry if I misunderstood lol... I maybe took that in the wrong sense of "sexy". I kinda misunderstood when you said "sexy". lol
Log in to reply
@Krishna Karthik – @Krishna Karthik but the epic question is that he is Steven chase or Lil Douga
Log in to reply
@Talulah Riley – Diggity Dougo. I bet he's doug.
Did you just change your name to Lil Doug ?????? Bro, you're a MADLAD!!!!!
What an absolute lad. You did it for the lads!!!!!
Log in to reply
@Krishna Karthik I can do anything bro.
Log in to reply
@Talulah Riley – What an absolute bloke. A true madlad.
@Krishna Karthik what does lads mean?
Log in to reply
@Talulah Riley – Just look it up on Urban Dictionary or something. It means a guy that's willing to do anything for the group.
Log in to reply
@Krishna Karthik – @Krishna Karthik yeah bro, I want real friends, not fake friends.
Log in to reply
@Talulah Riley
–
@Krishna Karthik
so I am now Lil Dougy, talk with me in a very respective manner.
Ok
Log in to reply
@Talulah Riley – Sir, what do you want me to do to improve the SEL-400 series? What do you say, boss?
Log in to reply
@Krishna Karthik – @Krishna Karthik yeah as a entrepreneur in SEL, I am improving my company to gain more profits.
@Talulah Riley – Nah, jkjk, madlad's just an internet term. Anyways, gtg.
@Krishna Karthik check my profile status..
Log in to reply
@Talulah Riley – @Krishna Karthik you have deleted you last message.
@Krishna Karthik
I am in US .
I am going to bed now. It is night here.
Good night.
Log in to reply
XD Alright; I'm going to work a little bit overtime; going to keep you posted when I've fixed the issue with the capacitor system.
Log in to reply
@Krishna Karthik what capacitor??
Log in to reply
@Talulah Riley – Bro I'm just roleplaying. SEL is an electrical engineering company.
Log in to reply
@Krishna Karthik – @Krishna Karthik I have to sleep bit early because tomorrow is my meeting in SEL company and @Steven Chase is also in meeting. So bye tomorrow we will meet in meeting.
@Talulah Riley – Goodnight boss.
@Krishna Karthik we are missing Steven chase in role playing.
Log in to reply
Yeah, ikr? I lost it when he said "Doug is indeed a good guy"
Here's some good words about Doug from him:
“Doug has made important contributions to many of SEL’s recent technological advances, has served as a mentor to many new engineers, and is a highly regarded member of our development group. His professionalism and technical expertise make him an excellent SEL representative for this symposium"
Log in to reply
@Krishna Karthik
Yeah bro.He said he is a very good guy. I think he is friend of Steven Chase.
Now I am going to bed.
Log in to reply
@Talulah Riley – Alright, see you bud. I just realised I have to practice my piano; totally forgot lol.
Log in to reply
@Krishna Karthik
–
@Krishna Karthik
Do you play piano?
By the way, I like singing very very much.
Do you also like?
Log in to reply
@Talulah Riley – I don't like singing that much; I'm kinda bad at singing lol. Look at my "About section". Scroll down. You'll see that I do play the piano :)
Log in to reply
@Krishna Karthik – @Krishna Karthik which piano you have? What is it's price?
Log in to reply
@Talulah Riley – I don't have a grand piano or anything like that, but I have a second hand upright (new). It's a good model; Bechstein. It only cost me around 10,000 AUD. The owner wanted to give it up so bad lol. That's such a good price for a Bechstein piano. Crazy, isn't it?
Anyway, yea, I saved up to buy it. So happy when I got it :)
@Talulah Riley – I mainly play classical composers like Chopin, Beethoven, Mozart, Bach, etc.
@Steven Chase
Please help me in this problem
If it is getting hard analytically, assume some values with your own and solve with python.
Thanks in advance.
@Novak Radivojević
Thanks for the solution.
I didn't understand how can we replace the sphere with point charge, can you elaborate more?
Thanks in advance.
Log in to reply
Hi, charged hemisphere and its equivalent point charge generate the same electric field vector over the spherical cap. Calculating flux in both cases would give the same result. I just felt that solving the problem this way would be nicer.
Log in to reply
@Novak Radivojević
But on what basis or proof we can say that point charge and spherical sphere can be treated same. ?
I am very curious about you method.
Thanks in advance.
@Novak Radivojević hey bro till now, I am not able to understand you solution?
@Novak Radivojević How can we replace sphere with point charge??
Log in to reply
Hey, sorry for ghosting you about this problem, it's just that both the sphere and the point charge generate the same electric field, and thus the same flux at points that are outside of the sphere. Electric field for both can be calculated as E = 4 π ϵ 0 r 2 Q , where r > R .
Log in to reply
@Novak Radivojević but how did you know that???
Log in to reply
@Talulah Riley – Well, formula for electric field of a point charge is known to be the one I mentioned in the previous comment. Formula for E field around a sphere can be derived by applying Gauss' Law, and after that you'll just get the same formula for point charge. I just skipped the part with Gauss' Law.
@Novak Radivojević Did you deleted you comment?
Problem Loading...
Note Loading...
Set Loading...
Nice one. Commented solution code is attached. I moved the source charge to ( 0 , 0 , − 2 ) and made the half sphere sit at the origin.