Composite divisors 1

Amongst all the integers n n such that n n \mid 2 n 2 2^{n}-2 and n n \mid 3 n 3 3^{n}-3 ; Find the sum of the smallest two composite integers.

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The answer is 1666.

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1 solution

Rishabh Tiwari
Jun 12, 2016

@Pi Han Goh , @Arturo Presa , @Calvin Lin @Sandeep Bhardwaj , @Brian Charlesworth , @Otto Bretscher , anyone? please help out to solve this problem ..thanking you in advance.

@Rishabh Tiwari , Do you mean that you had posted this problem. But, do not know how to solve it?

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I do know a logical solution, but don't know how to solve it step by step as I am a beginner in Number theory , hence posted it so that I can learn from fellow brilliantians. As of now no one has provided a good solution ; Can you please provide a solution sir ? Thanking you in advance!

Rishabh Tiwari - 5 years ago

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I am not one of the listed names, but Carmichael numbers satisfy Fermat's little theorem despite not being prime so we just sum the first two: 561+1105=1666.

Sal Gard - 5 years ago

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@Sal Gard Sorry, but as i said everyone is free to suggest & solve This question. But is there a proof ?

Rishabh Tiwari - 5 years ago

@Sal Gard Indeed, the solution would involve Carmichael numbers. But, they need to be co-prime with both 2 2 and 3 3 . 561 561 divides 3 3 . This makes it difficult to confirm if the solution should be 561 + 1105 = 1666 561+1105=1666 or 1105 + 1729 = 2834 1105+1729=2834 .

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