a a a . . . . m times ≡ 0 m o d ( am )
for all prime a’s
The congruence above is __________ .
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LOL yes :))
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You can define the hyperoperation as Tetration operator. so
n a = m times a a … a
can you plz tell that from where have you studied modular arithmetic ,you go in some coaching institute
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I do not go to any coaching institute , I have studied it on my own ....
For basics you may see Brilliant Wikis .... then for little higher NT you may see Elementary NT by Burton,....
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@A Former Brilliant Member – have you appeared in tallentex ,Olympiads by hbcse RMO and NMTC ,if appeared what were your ranks in those exam ,,please tell
J'ai choisi a=5, m=10k. Cela a rendu facile
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You have a counterexample whenever m isn't a power of a .
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Oui! Belle observation
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@Department 8 – That's german?
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@Kushagra Sahni – No i think its French
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@A Former Brilliant Member – Yes,that's French.
@Kushagra Sahni – Mais oui, c'est français, nicht Deutsch ;)
Google Translate jedermann?
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J'étudie la langue français à l'école
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@Department 8 – Magnifique! La langue de la philosophie, les mathématiques ... et de l'amour! ;)
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@Otto Bretscher – How many languages do you know comrade !!! @Otto Bretscher
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@A Former Brilliant Member – Indians also know atleast 3, Hindi English and the language of their ethnic community like Punjabi in my case.
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Let a = 2 and m = 3 . Then 2 2 2 fails to be divisible by 6.