Using constraint equations, show that the relationship between a 1 and a 2 can be expressed as a 2 = α × a 1 . Find α .
Assume both the pulleys and string are light and friction is absent everywhere. Where a 1 and a 2 are vectors.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
come on never thought negative answers allowed kept putting 7 and getting it wrong
Log in to reply
In Brilliant you cannot answer 7 three times, I think you have viewed solution
Log in to reply
yeah frustrated as i was getting same answer again and again nice problem btw
Log in to reply
@Rohith M.Athreya – try my nice problems " speck of dust" and "speck of dust returns" not original but very nice!!
@Rohith M.Athreya – Thanks, you were familiar about the trick ??
Log in to reply
@Raj Rajput – yeah we learnt stuff like this in detail
Log in to reply
@Rohith M.Athreya – You are in which class??
Bro Please write answer with direction or put a vector sign over acceleration in question.otherwise it seems we are talking about magnitude only unless a vector sign is there
Log in to reply
@Prakhar Bindal – Yes ,I will take care about that next time, it is handwritten cannot be edited ..... :)
Man! I was also having the same confusion.
I'm not very good at classical mechanics, how do you know that tension is inversely proportional to acceleration?
Log in to reply
Thats called virtual work method for constraints @Shaun Leong
Log in to reply
try my problem too, https://brilliant.org/problems/another-troublesome-cylinder/ .....btw i kept entering 7 and then entered random values as i got frustrated y the ans is not 7 !!
Log in to reply
@A Former Brilliant Member – yeah! nice problem :)
mention that a1 and a2 are vectors
Got wrong ! Entered 7 and saw the solution :( Btw Another short trick is using the formula 1/ 2^n -1 . And doing it verbally :)
sorry, i be confused by this questions, please can you make understand me? Tikka
Log in to reply
Read the solution once again, you will get it
Log in to reply
I not sure still. Korma
Log in to reply
@Pauline Salter – there is trick shown above, a relation used for finding relations between acceleration, velocities and displacement for 2 blocks that is T is invesely proportional to a . Assume acceleration of block 1 a and its tension t and acceleration of block 2 A and its tension T use proportionality relation, constant used will be cancelled and you will get relation.
Log in to reply
@Raj Rajput – make sense nows, thank s for helps. usually i find maths difficult so I do naan
Log in to reply
@Pauline Salter – who are you ??
Log in to reply
@Raj Rajput – My name is Pauline, I am old now so I saag (at maths)
sorry for my english bad Vindapoo
Problem Loading...
Note Loading...
Set Loading...