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8 solutions
I solved it :D :P
Write a solution. Notice to Brilliant:
Don't let users post so simple questions on the name of algebra for the sake of other users (who gave the heading "cool question"?). By the way the answer is 2.
It depends on which math we are using here. If it's base 10 then the answer is 2. However if it's binary, the answer is 10. :)))
suppose,
a = b
M u l t i p l y b o t h s i d e s b y b ,
a b = b 2
S u b t r a c t a 2 f r o m b o t h s i d e s a n d f a c t o r i z e :
a b − a 2 = b 2 − a 2
a ( b − a ) = ( b + a ) ( b − a )
Simplify and add 1 to both sides:
a = b + a
a + 1 = b + a + 1
Now since a=b (the starting point of this proof), we can write this as:
a + 1 = a + a + 1
a + 1 = 2 a + 1
And in the case where a=1, we have:
1 + 1 = 2 + 1
So, therefore,
1 + 1 = 3 .....................[proved]
1 + 1 = 3 ? .
Considering S u b t r a c t f r o m b o t h s i d e s a n d f a c t o r i z e
You can use \text{Subtract from both side and factorize}
appears as Subtract from both side and factorize
otherwise, it will be hard to understand the sentence.
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just look at the solution, where is the fault? if you can then tell me.otherwise this is right .
and thanks for the information,again.
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How did you get a = b and a b = b 2 ? . In other words, can you say which method you have used.
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@Munem Shahriar – there is no problem with that. the fault is not there. try to find.
u suppose that a=b, then a-b=0, so in 5th step where u have cancelled the factors (b-a) from both side it is false because it is of 0/0, form which is undefine...
1+1=2
This is the first operation that I learned when I was a kid. All of us must know this before advancing to more complicated like subtraction, multiplication and division.
1+1=2 still like a baby i like your style
nothing to say.. :)