Current

Electricity and Magnetism Level 1

The series circuit at the right depicts three resistors connected to a voltage source. The voltage source (ΔVtot) is a 110-V source and the resistor values are 7.2 Ω (R1), 6.2 Ω (R2) and 8.6 Ω (R3). Determine the current in the circuit.

The answer is 5.

10 solutions

Rahma Anggraeni
May 12, 2014

$I=\frac{V}{R}$

Since the resistors connected in series, so to determine the total value just adding all of it.

$I=\frac{110}{7.2+6.2+8.6}$

$I=\frac{110}{22}$

$I=\boxed{5}$

Diyanko Bhowmik
Mar 27, 2014

110/(7.2+6.2+8.6) = 110/22 = 5A.

hi..diyanko....can u plz explain how all the resistances add up??....2 are in parallel .....and 1 is in series...

Poorva Patel - 7 years, 2 months ago

No, all are in series . . . they add up to 22 ohms . . . . and then I=V/R . . . I=110/22=5A.

Diyanko Bhowmik - 7 years, 2 months ago

1st for parallel find Rq=(1/R1+1/R2) than Rq add with series R3 .its only for 2 parallel and one series circuit

Dhiraj Barman - 7 years, 2 months ago

I tried doing that.,.nd the answr is too complicated...so...but nw i got it that all are in parallel Thanx for the expaination:)

Poorva Patel - 7 years, 2 months ago

@Poorva Patel – I think all are in series. -_-

Diyanko Bhowmik - 7 years, 2 months ago

@Diyanko Bhowmik – Ya....it says that ur answr is ryte

Poorva Patel - 7 years, 2 months ago

110/(7.2+6.2+8.6) = 110/22 = 5 A

Supriya Mandal - 7 years, 1 month ago

5 A

Abhishek Dadhich - 7 years, 1 month ago

Akash Chature
Mar 29, 2014

as V=IR ,I=V/R ,,I=110/22=5 AMPERES

Karishma Mahanta
Jul 28, 2014

V=RI,,,,,,,,,,,resistors are in series.................R=7.2+6.2+8.6=22ohm...............I=V/R=110/22=5A

Vishakh Vr
May 13, 2014

As per ohm's law , we know that V = IR , I = V/R ...Here V= 110 V ... In the circuit resistors are connected in series ... so total resistance of the circuit is R1+R2+R3 Which is 22 ... then I = 110/22 = 5A