a car is revolving around a circular orbit with a velocity is given by
ω
=
e
t
what is the acceleration at t=0?.
Derails and assumptions:
Neglect friction.
Radius of the orbit is 200 m.
Report your answer with two decimal places.
Good luck!
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x = R c o s ( e t ) and y = R s i n ( e t ) so the acceleration on the x axis is R ( − e t s i n ( e t ) − e 2 t c o s ( e t ) and the acceleration on y axis is R ( e t c o s ( e t ) − e 2 t s i n ( e t ) so the acceleration on the x axis is 276.354 and on the y axis 60.2337 so the acceleration is the radical of 2 7 6 . 3 5 4 2 + 6 0 . 2 3 3 7 2 equal 282.842
hmm... they re just asking magnitude... it would ve been easier if u considered tangential and normal accelerations...
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yeah but I wanted to get back to the basics!
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Overrated ques
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@Gauri shankar Mishra – why? I guess the rating system in brilliant is good
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a ( t ) = ( a n 2 ( t ) + a t 2 ( t ) ) 2 1
a n ( t = 0 ) = ω 2 ( t = 0 ) r = r
a t ( t = 0 ) = r ( d t d ω ) t = 0 = r
So a ( t = 0 ) = r 2 2 1