Dedicated to my friends!!
How many real solutions are there to
x − 5 x 8 − 4 0 x 7 + 7 0 0 x 6 − 7 0 0 0 x 5 + 4 3 7 5 0 x 4 − 1 7 5 0 0 0 x 3 + 4 3 7 5 0 0 x 2 − 6 2 5 0 0 0 x + 3 9 0 6 2 5 = 0 ?
The answer is 0.
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1 solution
@parthlohomi which friends??
How did you analysed the numerator?
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Haha!!
I saw (x-5) and then divided the numerator and got (x-5)^7
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S you knew the expansion of (x-5)^7?
a tedious task I think , caught in a mistake while dividing the polynomial - what you will do?
As
( x − 5 ) 8 = t h e n u m e r a t o r
So it becomes
x − 5 ( x − 5 ) 8 = 0
This gives us the solution that x = 5
But this solution is not just as the denominator becomes 0 and
0 a n y t h i n g is not defined
So there are 0 solutions
. 0 × 1 . 6 = 0