Do you believe it's from NTSE#1

Three equal weights A,B.C of mass 2 kg each are connected through a pulley (frictionless and massless) as shown .The tension in the string connecting weights B and C in NEWTON is:

:


The answer is 13.33.

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1 solution

Satyajit Ghosh
Oct 11, 2015

After drawing free body diagrams we get the equations as follows, T 20 = 2 a 40 T = 4 a ( C o n s i d e r i n g B a n d C a s a s y s t e m ) W e g e t a = 20 / 6 m / s 2 N o w f o r B a n d C , 20 T = 2 a p u t t i n g a a s 20 / 6 w e g e t T a s 13.33 N T-20=2a\\ 40-T=4a(Considering\quad Band\quad C\quad as\quad a\quad system)\\ \Longrightarrow We\quad get\quad a=20/6m/s^{ 2 }\\ Now\quad for\quad B\quad and\quad C,\\ \Longrightarrow 20-T=2a\\ putting\quad a\quad as\quad 20/6\quad we\quad get\quad T\quad as\quad 13.33N

Same method, and I think you should trouble yourself a bit by using latex.

Kushagra Sahni - 5 years, 8 months ago

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Lol, it's in latex right now.

Satyajit Ghosh - 5 years, 8 months ago

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It wasn't some time back

Kushagra Sahni - 5 years, 8 months ago

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@Kushagra Sahni I did it after your comment!

Satyajit Ghosh - 5 years, 8 months ago

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@Satyajit Ghosh I Know Right.

Kushagra Sahni - 5 years, 8 months ago

In future, if you spot any errors with a problem, you can “report” it by selecting "report problem" in the “More” menu in the top right corner. This will notify the problem creator who can fix the issues.

E.g. The answer format had to be an integer, while the actual answer was a decimal.

Calvin Lin Staff - 5 years, 3 months ago

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