Digits and Numbers

Probability Level pending

How many 6-digit numbers can be formed with the 10 digits $0, 1, 2, 3, \ldots, 9$ , if repetitions are allowed?

60 900000

6^{5}

60480

1 solution

Hana Wehbi
May 26, 2016

The first digit can not be 0, so we have 9 choices for the first one, and since repetition is allowed we have 10, 10,... for the rest.

Thus, the answer is $9*10*10*10*10*10$ = $9*10^{5}$

Simple and easy question (+1):- May I ask you to use the LaTeX code \times in place of a *

Ashish Menon - 5 years ago

Yes Sir, why not? Trust me, i will always accept advices on Latex. I am new with Latex : {

Hana Wehbi - 5 years ago

First of all I am not a sir XD I am just 15. Next, I am sure you would eventually get better at it. I learnt LaTeX by editing brilliant wikis. $\ddot\smile$ . This website might help to learn some nice LaTeX.

Ashish Menon - 5 years ago

@Ashish Menon – Thanks dude. Sir, is another form of respect. I know you are just 15. SORRY :)

Hana Wehbi - 5 years ago

@Hana Wehbi – Hahah, sorry what for? You can search on the toolbar too for LaTeX guide under "notes". Many guides would open up.

Ashish Menon - 5 years ago

@Ashish Menon – For calling you sir. Thanks again.

Hana Wehbi - 5 years ago

@Hana Wehbi – Its ok. You're welcome.

Ashish Menon - 5 years ago

Digits and Numbers

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