Determine the number of integral solutions ( x , y , z ) with ∣ x ∣ , ∣ y ∣ , ∣ z ∣ distinct, of ∣ x ∣ ⋅ ∣ y ∣ ⋅ ∣ z ∣ = 1 2 .
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What about (1,-1,12).
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Yes, a very important point ! I should add more solution sets :- ( 1 , − 1 , 1 2 ) , ( − 1 , 1 , 1 2 ) , ( 1 , − 1 , − 1 2 ) , ( − 1 , 1 , − 1 2 ) . Thanks a lot, but since I can't change the solution ( there is no such option), I prefer to edit the question as ∣ x ∣ , ∣ y ∣ and ∣ z ∣ distinct. I hope that works fine. Thanks !
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Welcome Karthik. But I must say the question was really good.
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@Ankit Kumar Jain – Thanks a lot, I am glad that you felt so !
Great solution. Karthik I solved the problem.
A nice problem. I forgot abut the sign!
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Factorizing gives 12=1·2·2·3, and thus, for |x|,|y| and |z| to be distinct, the possibilities for the three absolute values |x|, |y|, |z| are (ignoring order) (1, 2, 6) and (1, 3, 4). Each of these can be ordered in six different ways, and then, for each of the six ways, we can have 0, 1, 2, or 3 of the integers positive, making a total of eight ways. Thus altogether there are 2 · 6 · 8 = 96 solutions to identify.