Divide and Rule

Once I performed a series of divisions where I got that the dividend is equal to remainder. Are my divisions flawed?

Note: I perform divisions for non-negative integers.


This problem is original.

Some may be flawed. Definitely flawed. Not flawed at all.

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2 solutions

Nihar Mahajan
Jun 15, 2015

If we let D D as the dividend , d d as the divisor , q q as the quotient and r r as the remainder , By division algorithm we have:

D = d q + r D=dq+r

But since D = r D=r , we cancel them from both the sides to get d q = 0 dq=0 .

Case 1: When d = 0 d=0 , my division is definitely flawed because I cannot divide a number by 0 0 .

Case 2: When q = 0 q=0 , implies that the dividend itself is 0 0 that is D = 0 D=0 , which is possible.

Hence , some of my divisions might be flawed,.

:3 :3 :3 :3 :3 :3 :3 :3 :3 :3 :3 :3 :3 :3 :3 :3 :3 :3

Mehul Arora - 5 years, 12 months ago

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:3^\infty :3

Nihar Mahajan - 5 years, 12 months ago

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( : 3 ) \boxed {{(:3)}^{\infty}}

Mehul Arora - 5 years, 12 months ago

sir, in which class you are?

Dev Sharma - 5 years, 12 months ago

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@Dev Sharma I am in 10th class.

FYI: Don't call me Sir. You "must" call me Nihar.

Nihar Mahajan - 5 years, 12 months ago

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@Nihar Mahajan are you preparing for olympiad

Dev Sharma - 5 years, 11 months ago

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@Dev Sharma Oh sorry , I didn't notice your comment before , since there were too many notifications. Anyways , I am preparing for olympiad (especially Maths and Astronomy).

Nihar Mahajan - 5 years, 11 months ago

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@Nihar Mahajan I want to contact you on your fb account, can i send you a friend request as i am thinking to prepare for olympiad/?

Dev Sharma - 5 years, 11 months ago

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@Dev Sharma Yeah , sure. :)

Nihar Mahajan - 5 years, 11 months ago

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@Nihar Mahajan your profile pic is IMO logo??

Dev Sharma - 5 years, 11 months ago

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@Dev Sharma Yes , it is.

Nihar Mahajan - 5 years, 11 months ago

@Nihar Mahajan Just curious. You like maths more or astronomy ?

Raven Herd - 5 years, 6 months ago

Same way !!

A Former Brilliant Member - 5 years, 6 months ago

gr8 solution :XD .........

Tootie Frootie - 5 years, 12 months ago

In case 2, if q = 0, D can be different from 0, but you can conclude that D < d and therefore D = r. for example dividing 4 by 6 we get 4 = 6*0 + 4.

Gabriel T. Vercelli - 5 years, 8 months ago

division could still be flawed anyway... Even if the dividend were different from remainder. It should be "not necessarily flawed" instead of "may be flawed"

Sam Reeve - 5 years, 6 months ago
Rwit Panda
Dec 7, 2015

"0 being the dividend" case cannot be forgot.

So it may not always be flawed :)

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