Do all look irrational?

Which of these numbers is/are rational?

1. π 2 1. \ \sqrt{\pi^2}
2. 0.8 3 2. \ \sqrt[3]{0.8}
3. 0.00016 4 3. \ \sqrt[4]{0.00016}
4. 1 3 4. \ \sqrt[3]{-1}

All 2 and 3 2 and 4 Only 4 None Only 3

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1 solution

Kay Xspre
Feb 8, 2016

π |π| is irrational. The other two may be reduced to 2 10 3 \frac{2}{\sqrt[3]{10}} and 2 10 10 4 \frac{2}{10\sqrt[4]{10}} , which is also irrational. Only 1 3 = 1 \sqrt[3]{-1} = -1 is rational

What about the other 2 values of (-1)^1/3?

Kushagra Sahni - 5 years, 4 months ago

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I think you make reason , it should be clarified, althought I answered good this question so it's the same for me.

Guillermo Templado - 5 years, 3 months ago

Not real number, nor does the other two choices of (2) and (4). This question only wants us to evaluate the value in real number.

Kay Xspre - 5 years, 4 months ago

What's π |\pi| ??? No sense of putting mod on π \pi as it is already positive.

Rishabh Jain - 5 years, 4 months ago

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Bhaiya square root yields positive values so that's why mod...

Department 8 - 5 years, 4 months ago

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What's the need to apply mod on something that's already positive!! ( π = 3.1415.. > 0 (\pi=3.1415..>0 )

Rishabh Jain - 5 years, 4 months ago

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@Rishabh Jain Hmmm..... That's strange may be @Kay Xspre would help

Department 8 - 5 years, 4 months ago

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@Department 8 One important question( it's irrelevant )..Who do you support among Lesnar, Reigns and Ambrose in the Triple Threat match for Wrestlemania against HHH..

Rishabh Jain - 5 years, 4 months ago

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@Rishabh Jain Lesnar the beast

Department 8 - 5 years, 4 months ago

@Rishabh Jain I put absolute value to satisfy the x 2 = x \sqrt{x^2} = |x| , as a number of people is likely to assume x 2 = ± x \sqrt{x^2} = \pm x

Kay Xspre - 5 years, 4 months ago

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