Find the next number in the series 1 , 1 , 1 , 2 , 3 , 5 , 9 , 1 8 , 3 5 , 7 5 , …
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it is the numbers of isomers of increasing alkanes, simply it was a non conceptual series it is the cramming part of chemistry
No!!!! @yash singh you should check the comments made by me, in pranjal's solution,so without thinking u can't call anything NON CONCEPTUAL.
I googled too and got the list:
1, 1, 1, 1, 2, 3, 5, 9, 18, 35, 75, 159, 355, 802, 1858, 4347, 10359, 24894, 60523, 148284, 366319, 910726, 2278658, 5731580, 14490245, 36797588, 93839412, 240215803, 617105614, 1590507121, 4111846763, 10660307791, 27711253769
See here .
Yeah! I googled it too!
That's simply the number of isomers of n − membered alkane. Here is the list.
@Mehul Chaturvedi This was a nice idea for proposing a problem. But I think this is not worth posting as the number of isomers cannot be calculated and it's almost impossible to draw all the possible isomers of higher alkanes. As you might know, there is no mathematical function defined for generating number of isomers. You might have kept it to lower alkanes like, at most 8.
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@Pranjal Jain there is a mathematical formula/function to calculate number of isomers
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I couldn't find a general formula. Can you type it here? Thanks @Mehul Chaturvedi
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@Pranjal Jain – actually that is taught in college @Pranjal Jain .And the fact is that I too couldn't understand that function it's quite complicated.
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@Mehul Chaturvedi – -_- Oh, I won't be pursuing chemical engg. in IIT.
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@Pranjal Jain – this year u would be appearing for IIT?
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@Mehul Chaturvedi – Yes...
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@Pranjal Jain – all d best
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@Mehul Chaturvedi – Thanks
@Mehul Chaturvedi – This was an easy question since I had memorised the first ten numbers , so I recognised it and looked up the 11th one !
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@A Former Brilliant Member – Seriously ? you have great capabilyty of memorising man ! But Just curious what inspire you to learn't isomers upto 10 ? I'am astonished, Is there any mathamatical approach to this problem ?
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@Deepanshu Gupta – Sorry for the late reply ! I had memorized it long ago in Class 11 when I wasn't sure if I could understand the concept of Isomerism .
I just love memorizing things like lists , phone numbers , roll numbers … and the list is endless !!
As for a Mathematical Approach , I don't think so that there is one .
@Pranjal Jain you may check it here
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This doesn't seem like an algebra question to me. It is an interesting fact, but I'm not sure how likely it would be to find next term with algebra alone. Might just be a polynomial of degree ten.
wow man ! How did you kill this ? I mean I can never imagine that these are isomers ..... Have you learnt some isomers ?
Even I know title is 'chemaths' , but still I can't imagine!
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I was having some so called research over isomers,just then the idea clicked in my rusty mind,and is presented in front of u.
just click on view wiki option just below the answer tab and you get the ultimate hint.
This is the number of isomers of membered alkane.
C15H32 has 4347 isomers
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This is a simple sequence of the number of structural isomers of the first ten alkanes.
So the answer will be the number of structural isomers of C 1 1 H 2 4 i.e 159