Do you know division?

You clearly didn't apply "dumbass theory of significant figures" correctly, it clearly states that you need to convert the numbers into word form before simplifying them.

Actually, Prasun forgets to elaborate on the three fundamental dumbass theorem of significant figures. I guess he is also new to this. Let me enlighten you with this.

It's a convention to use Part 1 of the theorem unless specified.

"Fundamental Dumbass Theorem of Significant Figures Part 1" states that you need to convert numbers to words before simplifying them, then, add the number of decimal points equal to the number of digits of the actual number in numerator: $\begin{aligned} \frac {17555}{555} &= &\frac { \text{ SEVENTEEN THOUSAND FIVE HUNDRED AND FIFTY FIVE}}{\text{FIVE HUNDRED AND FIFTY FIVE}} \\ &=& \text{SEVENTEEN THOUSAND < space > } \\ &=& \boxed{17000.00000} \\ \end{aligned}$

"Fundamental Dumbass Theorem of Significant Figures Part 2" is also like Part 1, but instead, once you cancel out the numbers, you must leave the number $\text{ONE}$ behind. For example, for the fraction $\frac {1462}{62}$ : converting to numbers, and cutting out $\text{SIXTY TWO}$ and converting back to numbers give $\frac {141}{1} = 141 \ < \text{ space } > \ = \boxed{141.000}$

"Fundamental Dumbass Theorem of Significant Figures Part 3" states that for a fraction with a prime as a denominator, apply Legendre Symbol on the fraction then followed by applying Fundamental Dumbass Theorem of Significant Figures Part 1, but uses the number of digits in the denominator. For example: $\frac {549}{67} = \left ( \frac {549}{67} \right ) = \left ( \frac {3^2 \cdot 61} {67} \right) = \left ( \frac {3}{67} \right )^2 \left ( \frac {61}{67} \right ) = -1$ . Now apply Part 1: $\boxed{-1.00}$ because there's two digits in the denominator.

I should write a Brilliant Wiki about this, as there are more dumbass theorems to cover.

Exactly!! That's what I did.

Same in my first attempt hahahahahaha :P

I also tried the same as yours..........