Above shows a long division. What is the sum of values of all the missing digits?
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How to solve this??Steps please..
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●Think of a number like this when it is multiplyed by anything gives last digit as 7 and 8 and is two digit no. .
U will here find divisor as
1
9
.
●Now in last two boxes since Remider is 0, this fills last two boxes as
3
′
s
,
8
.
●Now 2nd box from top...no. will be
5
7
=
(
1
9
×
3
)
....because tens digit given is five.
●Now u got quotient multiply this with divisor to get divident..
Now we find dividend as
6
3
0
8
.
●From last, 4th box
6
0
−
5
7
=
3
....here 0 can be any no. upto 6 but it will be 0 because from 6308(dividend).
→ You got that now?
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My approach is different from yours:
In the middle there is:
6_
7
The one on the left of 7 is either 5 or 6
If it is 6 then divisor
=
6
7
, then it is impossible to make a 5
in the hundred place
So it is 57
Then divisor is
1
9
or
5
7
To make a _8 in the digit place, the divisor has to be
1
9
.
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0 3 3 2 1 9 \enclose l o n g d i v 6 3 0 8 5 7 0 0 0 6 0 0 5 7 0 3 8 3 8 0 0 0
Therefore, Sum of missing digits 6 1 .