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Logic Level 3

Above shows a long division. What is the sum of values of all the missing digits?


The answer is 61.

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1 solution

0 3 3 2 1 9 \enclose l o n g d i v 6 3 0 8 5 7 0 0 0 6 0 0 5 7 0 3 8 3 8 0 0 0 \LARGE{ \begin{array}{rllll} \phantom{0}\ \boxed{\color{#3D99F6}{3}} \ \boxed{\color{#3D99F6}{3}} \ \boxed{\color{#3D99F6}{2}} && \\[-4pt] \boxed{\color{#3D99F6}{1}} \ \boxed{\color{#3D99F6}{9}} \ \enclose{longdiv}{\boxed{\color{#3D99F6}{6}} \ \boxed{\color{#3D99F6}{3}} \ \boxed{\color{#3D99F6}{0}}\ \boxed{\color{#3D99F6}{8}} }&& \\[-4pt] \underline{\boxed5 \ \boxed{\color{#3D99F6}{7}} \ \phantom0 \ \phantom0 \ \phantom0} && \\[-4pt] \boxed{6} \ \boxed{\color{#3D99F6}{0}} \ \phantom0 \ && \\[-3pt] \underline{\boxed{\color{#3D99F6}{5}} \ \boxed{7} \ \phantom0 \ } && \\[-3pt] \boxed{\color{#3D99F6}{3}} \ \boxed{8} && \\[-2pt] \boxed{\color{#3D99F6}{3}} \ \boxed{\color{#3D99F6}{8}} && \\[-2pt] \overline{ \phantom0 \ \phantom{0} \ \phantom0 \ } && \\[-2pt] \end{array} }

Therefore, Sum of missing digits 61 . \boxed{\color{#624F41}{61}}.

How to solve this??Steps please..

Sagar Shah - 5 years, 4 months ago

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●Think of a number like this when it is multiplyed by anything gives last digit as 7 and 8 and is two digit no. .
U will here find divisor as 19 \boxed{19} .
●Now in last two boxes since Remider is 0, this fills last two boxes as 3 s , 8 \boxed{3's , 8} .
●Now 2nd box from top...no. will be 57 = ( 19 × 3 ) \boxed{57=(19×3)} ....because tens digit given is five.
●Now u got quotient multiply this with divisor to get divident..
Now we find dividend as 6308 \boxed{6308} .
●From last, 4th box 60 57 = 3 \boxed{60-57=3} ....here 0 can be any no. upto 6 but it will be 0 because from 6308(dividend).


\rightarrow You got that now?

A Former Brilliant Member - 5 years, 4 months ago

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My approach is different from yours:
In the middle there is:
6_
7
The one on the left of 7 is either 5 or 6
If it is 6 then divisor = 67 =67 , then it is impossible to make a 5
in the hundred place
So it is 57
Then divisor is 19 19 or 57 57
To make a _8 in the digit place, the divisor has to be 19 19 .

展豪 張 - 5 years, 3 months ago

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@展豪 張 Good! :)

A Former Brilliant Member - 5 years, 3 months ago

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