Don't loose hope-2

In the figure shown, all surfaces are smooth and block A and wedge B have mass 10 kg and 20 kg respectively. Find the sum of normal reaction between block A and B, spring force and normal reaction of ground on block B.If the whole system is in equilibrium.

Take g= 10 m / s 2 10m/s^{2}

Sin(37)=3/5

It is not an original problem .


The answer is 392.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Steven Chase
Aug 18, 2020

There are a few problems here, given that the requested answer is in integer format. First, it needs to be stated that the gravitational acceleration is 10 10 . And then, the answer is not actually an integer, so it needs to be stated to round to the nearest whole number.

Aside from that, we are solving a system of four equations for four unknowns. The first two equations are for mass A and the last two are for mass B.

F 1 60.18 F 2 79.86 F 3 48.06 F 4 263.78 F 2 + F 3 + F 4 391.70 F_1 \approx 60.18 \\ F_2 \approx 79.86 \\ F_3 \approx 48.06 \\ F_4 \approx 263.78 \\ F_2 + F_3 + F_4 \approx 391.70

@Steven Chase very nice solution.

Talulah Riley - 9 months, 4 weeks ago

@Steven Chase ,i have updated the question,thanks!

Btw nice solution.

A Former Brilliant Member - 9 months, 4 weeks ago

Thanks for updating the problem statement by specifying that the system is in equilibrium.

Karan Chatrath - 9 months, 4 weeks ago

Log in to reply

It would be good to specify in the problem statement to take sin ( 3 7 ) = 0.6 \sin(37^{\circ}) = 0.6 as doing so will give the exact integer answer. In reality, sin ( 3 7 ) 0.6 \sin(37^{\circ}) \ne 0.6

Karan Chatrath - 9 months, 4 weeks ago

Log in to reply

@Karan Chatrath You were talking that, and now??
Isn't it a contradiction?

Talulah Riley - 9 months, 4 weeks ago

Log in to reply

@Talulah Riley I'm sorry, I don't understand what you are saying

Karan Chatrath - 9 months, 4 weeks ago

Because you have given an integer answer, you have to give the values of sin 37 ° \sin 37\degree and cos 37 ° \cos 37\degree as 3 5 \dfrac 35 and 4 5 \dfrac 45 respectively.

(1) Normal reaction force between the block and the wedge is 10 g cos 37 ° = 80 10g\cos 37\degree=80 N

(2) Spring force is 10 g sin 37 ° cos 37 ° = 48 10g\sin 37\degree \cos 37\degree=48 N

(3) Normal reaction of ground on the wedge is 20 g + 10 g cos 2 37 ° = 264 20g+10g\cos^2 37\degree=264 N

Therefore their sum is 80 + 48 + 264 = 392 80+48+264=\boxed {392} N.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...