Let's call a solid common to two right circular cylinders of equal radii
intersecting at right angles a
safe
.
(These are the two cylinders which intersect in the manner given above.)
(This is the
safe
.)
Find the volume of this safe .
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Relevant wiki: Volume of Revolution - Problem Solving
Let's define the "safe" by x 2 + z 2 ≤ 3 6 and y 2 + z 2 ≤ 3 6 . Then the horizontal cross section at z = z 0 is a square of area 4 ( 3 6 − z 0 2 ) , and the total volume is ∫ − 6 6 4 ( 3 6 − z 2 ) d z = 1 1 5 2